Q. There are 2 circles. 1 circle has its center as (0,5) and radius = 5 units. The other circle has its center as (12,0) and radius =12 units. A third circle is drawn which will pass through the center of the second circle and the two points of intersection of the other two circles. Find the radius of such a circle.
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The equation of the first circle is x2+(y−5)2=25
The equation of the second circle is (x−12)2+y2=144
Solving them together, we get the two points of intersection of both the circles as (0,0) and (169600,1691440).
Centre of the second circle is (0,5)
So the centre of the third circle ( say (h,k) ) must be equidistant from the three points (0,0) ;(169600,1691440) ;(0,5)
Using distance formula, find the value of h and k. Radius of the circle would be the h2+k2.
Do it yourself : Finding the values of h,k
@Calvin Lin @Chew-Seong Cheong @Satyajit Mohanty @Pi Han Goh @Nihar Mahajan and all others.pPlease help
Is Answer 6 units
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How? pls explain