Thought Of The Day_11_Planets

Consider a planet revolving around sun in elliptical orbit.

#Mechanics #Gravitation #Astrophysics #KeplerLaws #Solarsystem

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Comments

If I remember right, Kepler's second law states that an object in an elliptical orbit covers equal areas in equal times. Since the area described by the sun-planet radius along path ABC is greater than the area associated with path CDA, that means T(ABC) > T(CDA). So I'd say proposition (1) is correct.

Robin P - 6 years ago

Yeah! Did the same way.

A Former Brilliant Member - 6 years ago

I think its correct

Arnesh Issar - 6 years ago

Yeah same! Also it could because the planet slows down at the aphelion

Rohan Joshi - 4 months ago

Is the answer, option 1?

A Former Brilliant Member - 6 years ago

Yup option 1 is a right answer...!!

Rohit Gupta - 6 years ago

Yeah , correct!

Nihar Mahajan - 6 years ago

Option 1 is correct...bit late to see the question though....

Tushar Panda - 5 years, 12 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$