Torque

While calculating torque, we assume that the force to the moment is perpendicular to it. I was wondering, what would happen if its not perpendicular. Please help!

#Physics

Easy Math Editor

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Comments

Torque is r X F. Take the cross-product.

Abhishiekh Ramesh - 8 years ago

Use VECTORS.

Shourya Pandey - 8 years ago

If the force is not perpendicular, there are two ways of calculating the torque. I refer to this picture.

Splitting the force ( $F$ ) into two components, one perpendicular to the axis ( $F_h$ ) and one directly towards the axis ( $F_v$ ). Then the torque $\tau$ becomes $\tau=F_h l=Fl\sin(\theta)$ .
Projecting the arm so it's perpendicular to the force. Here, the torque becomes $\tau=Fl'=Fl\sin(\theta)$ . As you see, the two methods agree, and are actually the same thing.

Mattias Olla - 8 years, 1 month ago

if it is parallel,and u happen to be strong enough as to break the axis of rotation,linear motion takes place

Beakal Tiliksew - 8 years, 1 month ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$