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Math
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Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3
2×3
2^{34}
234
a_{i-1}
ai−1
\frac{2}{3}
32
\sqrt{2}
2
\sum_{i=1}^3
∑i=13
\sin \theta
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\boxed{123}
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Comments
Jeriel,
Let the coordinates be (x,y)
using the distance formula,
root{(2-x)^2 + (-4-y)^2}= root(1-x)^2+(-3-y)^2 [DISTANCE IS EQUAL AS ITS AN ISOSCELES TRI]
= (2-x)^2 + (-4-y)^2 = (1-x)^2+(-3-y)^2 ["^2" MEANS SQUARE]
= 4-4x+x^2+16-(-8y)+y^2= 1-2x+x^2+9-(-6y)+y^2 (USING (x+y)^2 FORMULA)
NOW, X^2 AND Y^2 GET CANCELLED FROM BOTH
=4-4x+16-(-8y)= 1-2x+9-(-6y)
= 20-4x+8y=10-2x+6y
= 10+2y=2x [taking x and y on different sides]
DIVIDING THIS BY 2;
= 5+y=x OR x=y+5
NOW WE HAVE X IN TERMS OF Y...
USING AREA FORMULA OF COORDINATES OF A TRIANGLE,
SUBSTITUTE THE VALUES,WRITE X AS 'Y+5'
THEN IT BECOMES A ONE VARIABLE EQN
EQUATE IT TO 9/2 AND U WILL GET 'Y'
THEN FIND 'X'
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Jeriel, Let the coordinates be (x,y) using the distance formula, root{(2-x)^2 + (-4-y)^2}= root(1-x)^2+(-3-y)^2 [DISTANCE IS EQUAL AS ITS AN ISOSCELES TRI] = (2-x)^2 + (-4-y)^2 = (1-x)^2+(-3-y)^2 ["^2" MEANS SQUARE] = 4-4x+x^2+16-(-8y)+y^2= 1-2x+x^2+9-(-6y)+y^2 (USING (x+y)^2 FORMULA) NOW, X^2 AND Y^2 GET CANCELLED FROM BOTH =4-4x+16-(-8y)= 1-2x+9-(-6y) = 20-4x+8y=10-2x+6y = 10+2y=2x [taking x and y on different sides] DIVIDING THIS BY 2; = 5+y=x OR x=y+5 NOW WE HAVE X IN TERMS OF Y... USING AREA FORMULA OF COORDINATES OF A TRIANGLE, SUBSTITUTE THE VALUES,WRITE X AS 'Y+5' THEN IT BECOMES A ONE VARIABLE EQN EQUATE IT TO 9/2 AND U WILL GET 'Y' THEN FIND 'X'