Tricky Puzzle

There are 10 barrels containing gold coins. In that, 9 barrels contains 1 gram gold coins and the other barrel contains 2 gram coins. Every coin looks to be same without any difference. As the barrels weigh more, so it cannot be lifted or moved from its place. There is a weighing machine which is allowed to weigh only once. How to find that which of the barrels contain 2 gram coins..?

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
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`\sum_{i=1}^3`	$\sum_{i=1}^3$
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Comments

Take n coins from the nth barrel. The deficiency from 110 grams is the number of the barrel with the 1 gram coins. For example, if the 6th barrel has the light coins, the coins will weigh 104 grams. 110-104 = 6.

John Chang - 7 years, 11 months ago

2 solutions. You could first JUST OPEN THE BARRELS and select the one that has the most coins; or you could play with luck and guess with 2 random barrels assuming that one has 2 grams of coins.

Nathan Blanco - 7 years, 11 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$