Hello, I have face a deadlock while trying to find the way to evaluate this identities. I'm curious that we need to use the trigonometry sum formula to find the answer of this problem, but I still cannot find the way to finish it, I always go back to the initial problem. Pls help me, so I can answer my curiosity.. Thanks
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2^{34}
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You can simplify this to 4sin13∘cos31∘cos7∘.
You use the following facts to simplify your expression:
1) sinA+sinB=2sin(2A+B)cos(2A−B)
(2) sinA−sinB=2sin(2A−B)cos(2A+B)
(3) cosA+cosB=2cos(2A+B)cos(2A−B)
(4) cosA−cosB=−2sin(2A+B)sin(2A−B)
If you want to know the proofs for these, they are pretty straightforward.
For example:
We can derive, sin(x+y)+sin(x−y)=2sinxcosy
Now, let x+y=A and x−y=B, and substitute in the above equation.
This will give you the proof for equation (1)
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thanks Aditya, now I've just got some knowledge about simplifying the trigonometric identities..:)
Hint: 53−39=14=25−11, so that suggests a place to start. Likewise, 53−25=28=39−11.
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what is this sir...I cant understand!
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Think about how to apply the hint, esp in light of the sum and product trigonometric formulas that Aditya mentioned.
Since 53−39=14, when we combine cos53+cos39, we will get cos253−39 as one of the terms in the product. Since 25−11=14, when we combine −(sin25+sin11), we will get cos225−11 as one of the terms in the product. This allows us to factor out the cos7 (which you can see in Aditya's answer) and then continue with the remaining terms.
Aditya your 4th identity is wrong as it should be B-A instead of A-B which is very important as it matters a lot in sin.
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The 4th identity can, alternatively, also have a negative sign, which I supposedly missed while posting my comment. Thanks.
awh!!
answer is 1.61077
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don't use a calc...
Hello..?? We are now in the 21st century... Use calculator or even more sophisticated computing devices like computers installed with math soft wares like mathlab, scilab and python. There are a lot of builtin functions in that three softwares,... one of which you can convert decimal to fraction with higher precision.. you type that in the console, let the software computes...
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You are missing the point. Calculators will only get you an approximate decimal answer. He wants an exact answer in trigonometric form. See Adiya's solution.