\( R sin( \alpha + \theta ) = a \text{ } cos( \theta ) + b \text{ } sin ( \theta ) \)
R2=a2+b2 R^2 = a^2 + b^2 R2=a2+b2
tan(α)=ba tan( \alpha ) = \dfrac{b}{a} tan(α)=ab
R>0,−π2<θ<π2 R > 0 , \dfrac{ - \pi }{ 2 } < \theta < \dfrac{ \pi }{ 2 } R>0,2−π<θ<2π
Similar to Cartesian −> Polar \text{ Similar to Cartesian } -> \text{ Polar } Similar to Cartesian −> Polar
Refer to classic proof of trig compound angle formulae in vector(Cartesian) form \text{Refer to classic proof of trig compound angle formulae in vector(Cartesian) form } Refer to classic proof of trig compound angle formulae in vector(Cartesian) form
Note by Lin Shun Hao 6 months, 2 weeks ago
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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\sin \theta
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