The integers a,b,c,d,e,f,ga, b, c, d, e, f, ga,b,c,d,e,f,g, none of which is negative, satisfy the following system of simultaneous equations:
a+b+c=2a + b + c = 2a+b+c=2
b+c+d=2b + c + d = 2b+c+d=2
c+d+e=2c + d + e = 2c+d+e=2
d+e+f=2d + e + f = 2d+e+f=2
e+f+g=2e + f + g = 2e+f+g=2
Find the maximum possible value of a+b+c+d+e+f+ga + b + c + d + e + f + ga+b+c+d+e+f+g
[UKMT Cayley Olympiad 201520152015, Q222]
Note by Yajat Shamji 7 months ago
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As all the equations are equal to the same thing, we know they must be equal by Euclid's Axiom (Things which are equal to the same thing are also equal to one another)
a+b+c=b+c+d=c+d+e=d+e+f=e+f+ga+b+c=b+c+d=c+d+e=d+e+f=e+f+ga+b+c=b+c+d=c+d+e=d+e+f=e+f+g
From the above equations, we can simplify to get →a=d=g,\to a=d=g,→a=d=g, b=eb=eb=e and c=fc=fc=f
So the equation we want to find the maximum possible value of gets simplified
a+b+c+d+e+f+g=a+b+c+a+b+c+a=2(a+b+c)+a=4+aa+b+c+d+e+f+g=a+b+c+a+b+c+a=2(a+b+c)+a=4+aa+b+c+d+e+f+g=a+b+c+a+b+c+a=2(a+b+c)+a=4+a
We know that a can't be lesser than 000 or greater than 222, and that it must be an integer. This leaves the possible options of 0,10, 10,1 and 222. All of these options will work, but 222 is the greatest value here.
Thus, the maximum value of the equation is 6\boxed{6}6
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@Yajat Shamji - Done :)
Correct!
But... different method.
@Yajat Shamji – Yet again I see...
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2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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You have until this Sunday, 3:00pm!
As all the equations are equal to the same thing, we know they must be equal by Euclid's Axiom (Things which are equal to the same thing are also equal to one another)
a+b+c=b+c+d=c+d+e=d+e+f=e+f+g
From the above equations, we can simplify to get →a=d=g, b=e and c=f
So the equation we want to find the maximum possible value of gets simplified
a+b+c+d+e+f+g=a+b+c+a+b+c+a=2(a+b+c)+a=4+a
We know that a can't be lesser than 0 or greater than 2, and that it must be an integer. This leaves the possible options of 0,1 and 2. All of these options will work, but 2 is the greatest value here.
Thus, the maximum value of the equation is 6
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@Yajat Shamji - Done :)
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Correct!
But... different method.
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