SOLVED MYSTERY...

WHY DO MIRAGE APPEAR? MY TEACHER SAID IT IS DUE TO REFRACTION BUT WHAT IS THE ACTUAL PROCESS

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
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`\frac{2}{3}`	$\frac{2}{3}$
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`\sum_{i=1}^3`	$\sum_{i=1}^3$
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Comments

It is, due to refraction.

Zahle Khan - 6 years, 6 months ago

could you explain me please..

vishwathiga jayasankar - 6 years, 5 months ago

I am sorry, I misunderstood your question.By the way, someone else has answered the question.If you still have not understood it, reply to this message.

Zahle Khan - 6 years, 5 months ago

Cold air is denser than warm air and, therefore, has a greater refractive index. As light travels at a shallow angle along a boundary between air of different temperature, the light rays bend towards the colder air. If the air near the ground is warmer than that higher up, the light ray bends upward, effectively being totally reflected just above the ground. Once the rays reach the viewer’s eye, the visual cortex interprets it as if it traces back along a perfectly straight "line of sight". However, this line is at a tangent to the path the ray takes at the point it reaches the eye. The result is that an "inferior image" of the sky above appears on the ground. The viewer may incorrectly interpret this sight as water that is reflecting the sky, which is, to the brain, a more reasonable and common occurrence. this is how mirage happens

S rohith - 6 years, 5 months ago

THANK YOU FOR REPLY ROHITH!!!

vishwathiga jayasankar - 6 years, 5 months ago

now it has became a solved mystery

S rohith - 6 years, 5 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$