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I am sorry, I misunderstood your question.By the way, someone else has answered the question.If you still have not understood it, reply to this message.
Cold air is denser than warm air and, therefore, has a greater refractive index. As light travels at a shallow angle along a boundary between air of different temperature, the light rays bend towards the colder air. If the air near the ground is warmer than that higher up, the light ray bends upward, effectively being totally reflected just above the ground.
Once the rays reach the viewer’s eye, the visual cortex interprets it as if it traces back along a perfectly straight "line of sight". However, this line is at a tangent to the path the ray takes at the point it reaches the eye. The result is that an "inferior image" of the sky above appears on the ground. The viewer may incorrectly interpret this sight as water that is reflecting the sky, which is, to the brain, a more reasonable and common occurrence.
this is how mirage happens
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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a_{i-1}
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\sin \theta
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It is, due to refraction.
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could you explain me please..
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I am sorry, I misunderstood your question.By the way, someone else has answered the question.If you still have not understood it, reply to this message.
Cold air is denser than warm air and, therefore, has a greater refractive index. As light travels at a shallow angle along a boundary between air of different temperature, the light rays bend towards the colder air. If the air near the ground is warmer than that higher up, the light ray bends upward, effectively being totally reflected just above the ground. Once the rays reach the viewer’s eye, the visual cortex interprets it as if it traces back along a perfectly straight "line of sight". However, this line is at a tangent to the path the ray takes at the point it reaches the eye. The result is that an "inferior image" of the sky above appears on the ground. The viewer may incorrectly interpret this sight as water that is reflecting the sky, which is, to the brain, a more reasonable and common occurrence. this is how mirage happens
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THANK YOU FOR REPLY ROHITH!!!
now it has became a solved mystery