In the above system the mass of the object suspended varies with function m(t), and the spring constant of the spring is k.
Let x(t) be the length of the spring as time t and x0 as the natural length of the spring
⇒dtd[m(t)x˙(t)]=m(t)g−kx(t)+kx0
Assuming m(t)=m0−wt,where w,m0 are constants
⇒(m0−wt)x¨(t)−wx˙(t)+kx(t)=m0g−wgt+kx0
Now will you solve the equation?
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Comments
This is too difficult to solve analytically. Try solving it numerically and show us the result.