Variable mass with spring

In the above system the mass of the object suspended varies with function m(t)m(t), and the spring constant of the spring is kk.

Let x(t)x(t) be the length of the spring as time tt and x0x_0 as the natural length of the spring

d[m(t)x˙(t)]dt=m(t)gkx(t)+kx0\Rightarrow \dfrac{d[m(t)\dot{x}(t)]}{dt}=m(t)g-kx(t)+kx_0 Assuming m(t)=m0wt,where w,m0 are constantsm(t)=m_0-wt,where\space w,m_0\space are\space constants (m0wt)x¨(t)wx˙(t)+kx(t)=m0gwgt+kx0\Rightarrow \boxed{(m_0-wt)\ddot{x}(t)-w\dot{x}(t)+kx(t)=m_0g-wgt+kx_0} Now will you solve the equation?

#Mechanics

Note by Zakir Husain
1 month, 2 weeks ago

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Comments

This is too difficult to solve analytically. Try solving it numerically and show us the result.

Krishna Karthik - 1 month, 1 week ago
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