Cross Product is only valid in R^3 or R^7. I am interested in knowing why it's not valid in 2D space.I tried to invoke it out while solving a proving problem and in the problem I took two 2D vectors and when did a cross over them got all thing along +Z axis x X y = z so how to get a physical sense or an intuition behind that (cross product invalid in 2D).
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
The structure of vector products in V3 (three-dimensional vector space over an arbitrary field), which correspond to the usual Euclidean vector product and any generalisation based on arbitrary symmetric bilinear forms, is very different to that in V7, where certain luxuries that are present in our original framework do not hold, e.g. the Jacobi identity and Lagrange's formula.
In fact, the idea of a vector product outside of V3 should not be tackled within the realm of linear algebra. Thus, we must look outwards and rely on tools from geometric algebra. The notion of exterior products being a subspace of vectors in Vn perpendicular to a number of vectors is easier to interpret geometrically and algebraically, and is an ideal tool for extending vector products outside of V3.
To answer your question directly, look up Hurwitz's theorem. Again, working outside linear algebra and extending to geometric algebra is much more intuitive and less taxing on the current framework.
Log in to reply
Help with this https://brilliant.org/discussions/thread/vector-analysis/