To verify that certain values are solutions to the given equation, we simply substitute them in and check. This is very similar to Trial and Error.
How many of the following pairs of integers are solutions to 2x+3y=20?
(2,3),(3,5),(4,4),(6,3),(10,0)
A) 1
B) 2
C) 3
D) 4
E) 5
Solution: Trying the first option, 2×2+3×3=4+9=13=20.
Trying the second option, 2×3+3×5=6+15=21=20.
Trying the third option, 2×4+3×4=8+12=20. This is a solution.
Trying the fourth option, 2×6+3×3=12+9=21=20.
Trying the fifth option, 2×10+3×0=20+0=20. This is a solution.
Thus, 2 of the pairs are solutions.
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2x+y=z,3x-y=0