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Math
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2 \times 3
2×3
2^{34}
234
a_{i-1}
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\frac{2}{3}
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\sqrt{2}
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\sum_{i=1}^3
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Comments
It works for any tetrahedron, regular or not. Let's say that the cross section area is a square function from the apex
A(z)=kz2
where k is some constant, and z is the distance from the apex to the cross section. Then we integrate this
∫0hkz2dz=31kh3=31(kh2)h=31Bh
where B=A(h) is the area at distance z=h from the apex. You should recognize the familiar pyramid formula, and you should realize that this works for any kind of base, provided that all the cross sections are similar in shape following the square function of the distance from the apex.
But, how is the base area a square function, couldn't it be anything else like dependent on two different variables rathere than one variable squared. For example: A(z1,z2)=k(z1)(z2)
If you have any 2D shape with a definite area, then similar shapes have areas equal to the first times the square of the ratio of size. For example, a given polygon may have area B, and the same thing but 1/3 the size will have area 1/9 B. The pyramid formula doesn't compute the constant k itself, that depends on the particular shape that the base and all the cross sections have, which is supposed to be all similar.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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\(
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or\[
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
It works for any tetrahedron, regular or not. Let's say that the cross section area is a square function from the apex
A(z)=kz2
where k is some constant, and z is the distance from the apex to the cross section. Then we integrate this
∫0hkz2dz=31kh3=31(kh2)h=31Bh
where B=A(h) is the area at distance z=h from the apex. You should recognize the familiar pyramid formula, and you should realize that this works for any kind of base, provided that all the cross sections are similar in shape following the square function of the distance from the apex.
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But, how is the base area a square function, couldn't it be anything else like dependent on two different variables rathere than one variable squared. For example: A(z1,z2)=k(z1)(z2)
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If you have any 2D shape with a definite area, then similar shapes have areas equal to the first times the square of the ratio of size. For example, a given polygon may have area B, and the same thing but 1/3 the size will have area 1/9 B. The pyramid formula doesn't compute the constant k itself, that depends on the particular shape that the base and all the cross sections have, which is supposed to be all similar.
Log in to reply
cool