Weightlessness and air pressure.

If anyone here has read "For the love of physics" by Walter Lewin , you might have come across a question he challenged the readers with in his chapter about pressure . The problem goes likes this : A ball of juice is floating in space . A glass is not needed as the juice is weightless . A astronaut carefully inserts a straw into the ball of juice , and he starts sucking on it .Will he able to drink this way ? You may assume the air pressure in the space shuttle is about 1 atmosphere . "

#Mechanics

Easy Math Editor

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`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
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Comments

yes

Jonathan Leland - 3 years, 2 months ago

Yes he will be able to drink Notice That the bubble inside has an excess pressure of 4T/R (T being surface tension) When he sucks into the straw,rupturing the bubble slightly,a pressure gradient develops (from high to low) And as such the bubble distorts and enters into the straw ,allowing the astronaut to drink

Suhas Sheikh - 3 years ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$