Weird problem

Main post link -> https://brilliant.org/assessment/s/geometry-and-combinatorics/845915/

I don't understand what we need to find in this problem...

I mean I don't understand the concept of 'expected'.

Does the answer demand that I count all the possibilities for consecutive heads like in case of occurrence of only one H, there is no possibility of getting a consecutive heads-pair.. And in case of two heads, there's a possibility of 24 because HH can occur at 24 distinct places in the toss .

Am I getting the problem right?

Easy Math Editor

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Comments

I think you are just misunderstanding the meaning of expected value but this should help. See side bar for parts 2 and 3.

Arkan Megraoui - 8 years, 2 months ago

I still do not understand how to use that concept in here...

Aasif Khan - 8 years, 2 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$