What is the charge on the capacotor?

Please help me with the problem in the image.(ignore the part written other than in english)

Q:Consider the situation shown in the figure. The capacitor A has a charge q on it whereas B is uncharged.The charge appearing on the capacitor B a long time after the switch is closed is:

Easy Math Editor

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Comments

Ans. should be either $(1)zero$ or $(2)\frac{q}{2}$

The negative charge $q$ on the right capacitor plate of A is equally distributed between itself and the left plate of capacitor b. So the charge on the plate is $-\frac{q}{2}$ . The (induced)charge on the other plate= $+\frac{q}{2}$ . If the question asks for the magnitude of charge on each plate of B, ans is $(2)\frac{q}{2}$ .

But if the question asks for the net charge on capacitor B, ans is zero.

Krishna Jha - 7 years, 9 months ago

Yep, that's what I thought too.

Rohan Rao - 7 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$