Where can I get to solve C and C++ language problems?
Hi..I am Sushmita. Can I get to practice more of C and C++ language problems instead of Python language ?? Or where can I get to practice them ? I was never taught Python language so I am not too familiar with it.
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a_{i-1}
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Comments
Indeed, the problems in Brilliant.org are open for all languages. You don't have to solve them with Python but it is nice to post a solution with Python instead of other languages (note that Python is the easiest language for most people and it is mainly focused on Brilliant.org).
There are many C / C++ tutorial when you search it on Google like C Tutorial and C++ Tutorial.
To kick start the practice, Brilliant.org is well enough. For challenging one, you can search more about "Competitive Programming".
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Indeed, the problems in Brilliant.org are open for all languages. You don't have to solve them with Python but it is nice to post a solution with Python instead of other languages (note that Python is the easiest language for most people and it is mainly focused on Brilliant.org).
There are many C / C++ tutorial when you search it on Google like C Tutorial and C++ Tutorial.
To kick start the practice, Brilliant.org is well enough. For challenging one, you can search more about "Competitive Programming".
i made this problem based on c++ language https://brilliant.org/community-problem/an-interesting-problem-102/?group=fFPS13Kbo1lV
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Hey, I was just solving the question but got stuck. Is there any theorem or something for reducing abcmodd to something easily computable?
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yes there is, something called "divide and conquer" , and you also need some basic programming
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