Why?

If $a+b=c$ then ${ a }^{ 3 }+{ b }^{ 3 }\overset { ? }{ = }{ c }^{ 3 }={ \left( a+b \right) }^{ 3 }$

#Algebra

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`bold` or `__bold__`	bold
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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

I do not understand what you are trying to ask.

Calvin Lin Staff - 5 years, 8 months ago

I can't understand why is $a^3 + b^3 = c^3$ equates to $(a+b)^3 = c^3$ if $a+b=c$ . I really tried hard to understand but I failed.

JohnDonnie Celestre - 5 years, 8 months ago

try again what do you ask

yudi kuswara - 5 years, 7 months ago

I can't understand the last statement starting from "so this problem is equivalent to .. "

JohnDonnie Celestre - 5 years, 7 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$