Consider a quadrilateral ABCDABCDABCD . Find the necessary and sufficient condition with proof so that there exists a point PPP in the interior of ABCDABCDABCD such that A(PAB)=A(PBC)=A(PCD)=A(PDA)A(PAB)=A(PBC)= A(PCD)= A(PDA)A(PAB)=A(PBC)=A(PCD)=A(PDA).
A( ) represents Area\text{A( ) represents Area}A( ) represents Area
Nice solutions are always welcome!
Note by Nihar Mahajan 6 years, 1 month ago
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Such a point PPP exists if and only if one diagonal bisects the area of the quadrilateral.
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Can you please provide the proof sir ?
Sir, thanks for your answer.But it may be more beneficial for us if you post a nice proof.
Now that you know the right condition, you should try proving it.
Sir, actually this problem is from the homework of our class, and our sir has a different condition- P exists iff one diagonal bisects the other.
Yeah , thats why I posted this as a note.
@Nihar Mahajan – Did you get a proof
@Pranav Kirsur – I got the proof for the condition- P exists iff one diagonal bisects the other.I did not get proof for the condition that Jon Hausmann has posted.
@Nihar Mahajan – yes,same
In a quadrilateral, the conditions "one diagonal bisects the area" and "one diagonal bisects the other diagonal" are equivalent.
@Jon Haussmann – Oh yes, thank you for pointing that out to me
@Calvin Lin @Brian Charlesworth @Trevor Arashiro@Pi Han Goh @Chew-Seong Cheong @Mehul Arora @Sharky Kesa @Sanjeet Raria @Sudeep Salgia @Ronak Agarwal @everyone help us.
Nihar, Tujhe pata hai bhai ki Mujhe Geometry nahi aati :3 Jo Bhi Ho. Thanks For @Mentioning Me :D
I mentioned you so that you will have something interesting in geometry. ;)
@Nihar Mahajan – Yeah, Thanks! :) :D :)
me , @Kalash Verma @Harsh Shrivastava @CH Nikhil are in need of a nice solution.Thanks!
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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> This is a quote
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Such a point P exists if and only if one diagonal bisects the area of the quadrilateral.
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Can you please provide the proof sir ?
Sir, thanks for your answer.But it may be more beneficial for us if you post a nice proof.
Log in to reply
Now that you know the right condition, you should try proving it.
Sir, actually this problem is from the homework of our class, and our sir has a different condition- P exists iff one diagonal bisects the other.
Log in to reply
Yeah , thats why I posted this as a note.
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In a quadrilateral, the conditions "one diagonal bisects the area" and "one diagonal bisects the other diagonal" are equivalent.
Log in to reply
@Calvin Lin @Brian Charlesworth @Trevor Arashiro@Pi Han Goh @Chew-Seong Cheong @Mehul Arora @Sharky Kesa @Sanjeet Raria @Sudeep Salgia @Ronak Agarwal @everyone help us.
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Nihar, Tujhe pata hai bhai ki Mujhe Geometry nahi aati :3 Jo Bhi Ho. Thanks For @Mentioning Me :D
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I mentioned you so that you will have something interesting in geometry. ;)
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me , @Kalash Verma @Harsh Shrivastava @CH Nikhil are in need of a nice solution.Thanks!