Why does (-1)(-1)=1

I think you guys will know that (-1)(-1)=1 as me too, however a lot of students still being confused of this! Therefore, I want someone to explain this simple thing with different ways that the students will know instantly.

Example

(-1)(-1)

=(-1)(-1)-1+1

=(-1)(-1+1)+1

=0+1

=1

#Algebra

Note by Isaac Yiu Math Studio
1 year, 10 months ago

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1 vote

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Comments

The proof I have isn’t very simple, but it shows that (a)(b)=ab(-a)·(-b) = ab is a direct consequence of the properties of numbers (or what we defined them to be). These properties are, of course, the following:

  1. Associative law - addition

    a+(b+c)=(a+b)+ca+(b+c)=(a+b)+c

  2. Additive identity

    a+0=0+a=aa+0=0+a=a

  3. Additive inverse

    a+(a)=(a)+a=0a+(-a)=(-a)+a=0

  4. Communtative law - addition

    a+b=b+aa+b=b+a

  5. Associative law - multiplication

    a(bc)=(ab)ca· (b· c)=(a· b)· c

  6. Multiplicative identity

    a1=1a=aa· 1=1· a=a

  7. Multiplicative inverse

    aa1=a1a=1a· a^{-1}=a^{-1}· a=1

  8. Communtative law - multiplication

    ab=baa·b=b·a

  9. Distributive law

    a(b+c)=ab+aca·(b+c)=a·b+a·c


Ok, now the rules are set and we can prove that (a)(b)=ab(-a)·(-b) = ab.

Note that (a)(b)=(ab)(-a)· (b)=-(a· b), so (a)(b)+[(ab)]=(a)(b)+(a)b(-a)· (-b)+[-(a· b)]=(-a)· (-b)+(-a)· b =(a)[(b)+b]=(-a)· [(-b)+b] =(a)0=(-a)· 0=0.=0.

Now adding (ab)(a· b) to both sides gives us (a)(b)=ab.(-a)· (-b)=a· b.

Alex Greist - 1 year, 10 months ago

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Thanks for your help XD

Isaac YIU Math Studio - 1 year, 10 months ago
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