Wrong solution for "a badminton match"?

Re. this problem:

https://brilliant.org/community-problem/a-badminton-match-that-can-go-on-forever/?group=83R4PUpcVTyt

I'm sure I have solved it but the correct solution isn't accepted. I submitted a request to Brilliant about this but got not response. Has anyone else had the same issue?

(I'm not posting my solution here, in order to not spoil the problem for those that haven't solved it yet).

#Combinatorics

Easy Math Editor

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`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

When going to the problem, people agree the answer is incorrect.

Daniel Chiu - 7 years, 5 months ago

Thanks. I'll wait for it to be updated I guess :)

Matt McNabb - 7 years, 5 months ago

Hey Matt, this was a problem submitted by a user. It looks like the author of the problem corrected his mistake and people discussed the correct solution in the solution discussions.

Suyeon Khim Staff - 7 years, 5 months ago

Thanks, the staff have changed the solution now so everyone who entered the right value but originally got marked wrong should now have it marked right!

Matt McNabb - 7 years, 5 months ago

Bumping this, can an admin comment? It still hasn't been fixed and I would like my rating points back if nothing else..:)

Matt McNabb - 7 years, 5 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$