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The only thing I know is that it is less than 3, because of an identity by Ramanujan.Since it is above 2.9, we can find a good approximation.I dont think a closed form exists.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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Please enter the answer correct to 3 decimal places.
And also give full step solutions (as much as possible) , bcs. I haven't figured out yet!
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Wait....you changed the problem -_- I was working on the previous one :V
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Haha XD
I don't have any solution but out of curiosity, just to find out, I approximated it and got 2.911.
I made an equation ((((x-1)^2-2)^3-3)^4-4)^4........=x which gives 2.911
I think that the answer is about 2.911
Ramanujan maybe?
The only thing I know is that it is less than 3, because of an identity by Ramanujan.Since it is above 2.9, we can find a good approximation.I dont think a closed form exists.
please solve and post a nice solution to this
Awesome question!
Using 12 or above to starts iteration gives equal amount precision, about 50 digits.
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Same method, but did it manually.
Then does your number have a symbol, I mean Greek symbol or anything?
Thanks for all your suggestions. I will post it into a question.