-1 problem

Algebra Level 1

Take i = − 1 i = \sqrt{-1} . What is the value of ( − 1 ) 2 \left ( \sqrt{-1} \right)^2 ?

14 -1 No answer 999999999999999

Alan Sleh by Alan Sleh , 24, USA

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1 solution

Venkatachalam J
Apr 18, 2017

Solution1:

( − 1 ) 2 = ( − 1 1 / 2 ) 2 = − 1 (\sqrt{-1})^2= (-1^{1/2})^2 =-1

Solution2:

we know that i 2 = − 1 , t h e r e f o r e ( − 1 ) 2 = ( i 2 ) 2 = i 2 = − 1 i^2=-1, therefore (\sqrt{-1})^2=(\sqrt{i^2})^2 =i^2 =-1

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Not bad. but i= lots of other things, too. What's the square root of -.01 ?

Alan Sleh - 4 years, 1 month ago

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Solution for square root of -0.01= − 0.01 = − 1 / 100 = − 1 / 10 \sqrt{-0.01}= \sqrt{-1/100} =\sqrt{-1} /10

Venkatachalam J - 4 years, 1 month ago

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wrong, -1/10 x -1/10 = 1/100

Alan Sleh - 4 years, 1 month ago

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@Alan Sleh – can you explain in detail. how the square root of -0.01 will be 1/100

Venkatachalam J - 4 years, 1 month ago

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@Venkatachalam J – Negative x negative = positive. try on calculator.

Alan Sleh - 4 years, 1 month ago

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@Alan Sleh – I know negative x negative = positive. Your new question is "What's the square root of -.01 ?". I am not clear where the negative x negative number coming. Can you clear me what you are talking about. Once again check my solution and give me your feed back. (Or) what is your answer for "square root of -.01 ?"

Venkatachalam J - 4 years, 1 month ago

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@Venkatachalam J – Never mind...

Alan Sleh - 4 years, 1 month ago

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