Take $i = \sqrt{-1}$ . What is the value of $\left ( \sqrt{-1} \right)^2$ ?

14
-1
No answer
999999999999999

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Solution1:

$(\sqrt{-1})^2= (-1^{1/2})^2 =-1$

Solution2:

we know that $i^2=-1, therefore (\sqrt{-1})^2=(\sqrt{i^2})^2 =i^2 =-1$