The diagonal of the square with side 100 cm can be expressed as a × b c m and b is Square Free.
Then X=ab
Let Y be the number of trailing zeroes in 100!
Let the roots of the quadratic equation x 2 + 1 0 0 x + 8 1 9 be p and q
Then p 2 + q 2 = Z
Let A be the number of trailing zeroes in (X+Y+Z)!
Find X + Y + Z + A
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A faster way to calculate Z : ( p + q ) 2 − 2 p q = 1 0 0 2 − 2 ∗ 8 1 9
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That's what is newton's identity!
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Sorry I was confused !
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@A Former Brilliant Member – Well , refer this page . I hope its clear now . Thanks!
Thanks for not changing the answer , else I would have had to go through all the calculations again!
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No worries.The question is still the original and the same! No need to thank me for that!
Got it right! Same method , the only difference is in 3rd step I used newton's identity...
For trailing zeroes, I used Legendré formula for the greatest power of 5 in n ! to find number of trailing zeroes in both cases, Vietà's formula for the algebra problem and Pythagoras theorem for the geometry problem.
nice analysis. same as mine
There is an error in the first para,
Diagonal can be also written as 50 root 8
Yes sir... But the simplest answer is 100 root 2 as a diagonal is side of the square multiplied root 2
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I think u must mention in the question that b is 'square free' or 'independent of square" .
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I will just give away the answers.... I encourage you to solve them on your own.
The diagonal of the square can be expressed as 1 0 0 × 2 . Hence, X=200
The number of trailing zeroes in 100! is 24
The roots are -91 and -9... Therefore, Z= 8362
X+Y+Z = 8586. Therefore, the number of trailing zeroes in 8586! is 2143. Hence, A= 2143.
Adding them all up, you get 10729.
Cheers! :)