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Calculus Level 5

If, A = 0 1 ( i = 0 2014 x i ) d x 0 ( e t e 2 t t e 2016 t t e t ) d t A=\int _{ 0 }^{ 1 }{ \left( \sum _{ i=0 }^{ 2014 }{ { x }^{ i } } \right) dx } -\int _{ 0 }^{ \infty }{ \left( \frac { { e }^{ -t }-{ e }^{ -2t }-t{ e }^{ -2016 } }{ t-t{ e }^{ -t } } \right) dt }

Find: 10000 A \\ \left\lfloor 10000A \right\rfloor

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The answer is 5772.

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1 solution

Tanishq Varshney
Sep 30, 2015

ψ ( s + 1 ) = γ + 0 1 1 x s 1 x d x ψ ( s ) = 0 ( e t t e s t 1 e t ) d t \large{\psi \left( s+1 \right) =-\gamma +\displaystyle\int _{ 0 }^{ 1 }{ \frac { 1-{ x }^{ s } }{ 1-x } } dx\\ \\ \psi \left( s \right) =\displaystyle \int _{ 0 }^{ \infty }{ \left( \frac { { e }^{ -t } }{ t } -\frac { { e }^{ -st } }{ 1-{ e }^{ -t } } \right) } dt}

where γ \gamma is Euler Mascheroni constant \text{Euler Mascheroni constant} and its value is equal to 0.5772156 0.5772156 .

A = γ \large{A=\gamma}

Make it interesting a little bit. Prove both the statements that you have written. And I have something different too. Try to find the answer without even considering digamma function since the answer doesn't include it.

Kartik Sharma - 5 years, 8 months ago

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Solution without digamma function will become too tedious.

Aditya Kumar - 5 years, 8 months ago

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No, I don't think so. Use the general definition of γ \gamma .

Kartik Sharma - 5 years, 8 months ago

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@Kartik Sharma This method can also be termed as a definition of Euler mascheroni constant.

Aditya Kumar - 5 years, 8 months ago

@Kartik Sharma Can u post ur solution?

Aditya Kumar - 5 years, 8 months ago

hey can anyone of u post a solution to this

Tanishq Varshney - 5 years, 8 months ago

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I brought the answer in an integral form. But I couldn't get a good substitution to get the question in that form.

Aditya Kumar - 5 years, 8 months ago

Same method :). Thanks for posting the solution! BTW u r in which college?

Aditya Kumar - 5 years, 8 months ago

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