If, A = ∫ 0 1 ( i = 0 ∑ 2 0 1 4 x i ) d x − ∫ 0 ∞ ( t − t e − t e − t − e − 2 t − t e − 2 0 1 6 ) d t
Find: ⌊ 1 0 0 0 0 A ⌋
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Make it interesting a little bit. Prove both the statements that you have written. And I have something different too. Try to find the answer without even considering digamma function since the answer doesn't include it.
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Solution without digamma function will become too tedious.
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No, I don't think so. Use the general definition of γ .
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@Kartik Sharma – This method can also be termed as a definition of Euler mascheroni constant.
@Kartik Sharma – Can u post ur solution?
hey can anyone of u post a solution to this
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I brought the answer in an integral form. But I couldn't get a good substitution to get the question in that form.
Same method :). Thanks for posting the solution! BTW u r in which college?
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ψ ( s + 1 ) = − γ + ∫ 0 1 1 − x 1 − x s d x ψ ( s ) = ∫ 0 ∞ ( t e − t − 1 − e − t e − s t ) d t
where γ is Euler Mascheroni constant and its value is equal to 0 . 5 7 7 2 1 5 6 .
A = γ