For each number
$n$
, we define the
**
Digital Root
**
of
$n$
in the following manner: Take the sum of the digits to obtain a new number. Repeat this process until the result is a single digit.

Find the digital root of $\underset { 2016\text{ times} }{ \underbrace { 2016\ldots2016 } }$ .

As an explicit example, for $n=3487$ , $3487\quad \rightarrow \quad 3+4+8+7=22\quad \rightarrow \quad 2+2=4 \; .$ Therefore, the digital root of 3487 is 4.

**
Clarification
**
: In the number above, 2016 appears 2016 times in its decimal representation.

The answer is 9.

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Since the digital sum of 2016 = 9 So no matter how many time 2016 is there, the digital sum will always be 9.

Because every multiple of 9 has digital sum of 9...that's why that number is divisible by 9.