24 trouble
From how many numbers between 0 to 9 you can get 24 repeating the same number thrice?
The valid operations are + - * / ! ^ sqrt , sigma and decimal(multiple uses allowed)
Where sigma(n) means sum of all the numbers from 1 to n.
Note: Do not use any other number in power or something else. Use the same number only.
Note: Write .8 instead of 0.8 so that additional number is not there.
Note: sqrt is the square root and ! Is factorial.
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1 solution
24=((sigma(0!+0!)+0!))!
24=(sigma(1+1)+1)!
24=22+2
24=3^{3}-3
24=4!+4-4
24=5!/(sqrt5*sqrt5)
24=((6/(.6))-6)!
24=sigma7-(sigma7/7)
24=8+8+8
24=(sigma9/sqrt9)+9