From how many numbers between 0 to 9 you can get 24 repeating the same number thrice?

The valid operations are + - * / ! ^ sqrt , sigma and decimal(multiple uses allowed)

Where sigma(n) means sum of all the numbers from 1 to n.

Note: Do not use any other number in power or something else. Use the same number only.

Note: Write .8 instead of 0.8 so that additional number is not there.

Note: sqrt is the square root and ! Is factorial.

7
8
6
9
10
5

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24=((sigma(0!+0!)+0!))!

24=(sigma(1+1)+1)!

24=22+2

24=3^{3}-3

24=4!+4-4

24=5!/(sqrt5*sqrt5)

24=((6/(.6))-6)!

24=sigma7-(sigma7/7)

24=8+8+8

24=(sigma9/sqrt9)+9