24 trouble

From how many numbers between 0 to 9 you can get 24 repeating the same number thrice?

The valid operations are + - * / ! ^ sqrt , sigma and decimal(multiple uses allowed)

Where sigma(n) means sum of all the numbers from 1 to n.

Note: Do not use any other number in power or something else. Use the same number only.

Note: Write .8 instead of 0.8 so that additional number is not there.

Note: sqrt is the square root and ! Is factorial.

7 8 6 9 10 5

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1 solution

Prince Loomba
Aug 11, 2017

24=((sigma(0!+0!)+0!))!

24=(sigma(1+1)+1)!

24=22+2

24=3^{3}-3

24=4!+4-4

24=5!/(sqrt5*sqrt5)

24=((6/(.6))-6)!

24=sigma7-(sigma7/7)

24=8+8+8

24=(sigma9/sqrt9)+9

@Prince Loomba , Hi, i saw that once u uploaded a pic of fiitjee rmo compendium on brilliant. I wanted to ask that do u still have that book?

Vilakshan Gupta - 3 years, 9 months ago

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Sorry but I am in college now so I dont have any books of fiitjee or allen left

Prince Loomba - 3 years, 9 months ago

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but can u manage from somewhere to just send a pic of front cover of that book...f possible

Vilakshan Gupta - 3 years, 9 months ago

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@Vilakshan Gupta Nope sorry

Prince Loomba - 3 years, 9 months ago

Actually i want a pic of front cover of that book.

Vilakshan Gupta - 3 years, 9 months ago

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