2x+1...square rooted?

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If x + 1 = 201 4 2 + 201 5 2 x+1=2014^{2}+2015^{2} , what is 2 x + 1 \sqrt{2x+1} ?


The answer is 4029.

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2 solutions

May Lai
Jan 29, 2014

First we move the +1 to the right side and we get x=2014^2+2015^2-1 Factoring 2015^2-1 we get (2015+1)(2015-1) which equals 2016x2014 For x=2014^2+2014x2016 we take 2014 out. Thus we get x=2014(2014+2016)=2014x4030 2x=2x2014x4030=4028x4030=(4029-1)(4029+1)=4029^2-1 2x+1=4029^2 Therefore the square root of 2x+1 equals to 4029

I'll never use iPad to type those numbers and signs again:-(

Oh... I think you might have a better solution than I do... I didn't factor...

Finn Hulse - 7 years, 4 months ago

Dear Victor

Please state your source for this question and all questions you post

Wei Jie Tan - 7 years, 4 months ago

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If not, refrain from posting questions

Thank you

Wei Jie Tan - 7 years, 4 months ago

Sure, 'D D'

Victor Loh - 7 years, 4 months ago

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You know who I am?

Wei Jie Tan - 7 years, 4 months ago

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Of course. Do you mind me stating your name?

Victor Loh - 7 years, 4 months ago

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@Victor Loh You still did not state the source

Wei Jie Tan - 7 years, 4 months ago

I know you hate this question XD

Victor Loh - 7 years, 4 months ago
Finn Hulse
Jan 29, 2014

The sum of 2014 and 2015... Very strange... I worked it out with a calculator but it appears that the answer is 2014 plus 2015. Okay, I'm going to prove this as I go along. First we substitute x into the equation that we are trying to solve. The square root of 2 times 2014 squared plus 2 times 2015 squared minus one. Taking the square root, we find that we can break it into two parts: the square root of 2014 squared and the square root of 2015 squared.... Or just 2014 plus 2015, 4029.

TO GENERALIZE THE PROBLEM

Consider 2 numbers a , b a, b where b = a + 1 b=a+1

x + 1 = a 2 + b 2 x+1=a^{2}+b^{2}

substitute b = a + 1 b=a+1

x + 1 = a 2 + ( a + 1 ) 2 x+1=a^{2}+(a+1)^{2}

x + 1 = a 2 + a 2 + 1 + 2 a x+1=a^{2}+a^{2}+1+2a

x = 2 a 2 + 2 a x=2a^{2}+2a

Now substitute the value of x in given equation

2 x + 1 \sqrt{2x+1}

2 ( 2 a 2 + 2 a ) + 1 \sqrt{2(2a^{2}+2a)+1}

4 a 2 + 4 a + 1 \sqrt{4a^{2}+4a+1}

If you observe, the given equation can be factorised

( 2 a + 1 ) 2 \sqrt{(2a+1)^{2}}

2 a + 1 2a+1

a + a + 1 a+a+1

ie a + b a+b

So the value of 2 x + 1 = a + b \sqrt{2x+1} = a+b

Ans 4029 \boxed{4029}

Anirudha Nayak - 7 years, 4 months ago

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This is a lot easier than mine, almost no calculations.

May Lai - 7 years, 4 months ago

I'm just kinda confused that how you broke it into two parts, could you explain it to me?

May Lai - 7 years, 4 months ago

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