The answer is 50180.

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Let the side length of the small equilateral triangle and square be $1$ . Joint the top vertices of the two equilateral triangles with a line. Then we note that the side length of the large equilateral triangle is $1+2\sqrt 3$ . Since the area of of a same shaped figure is directly promotional to the square of linear dimension, the ratio of the area of the small equilateral triangle to the area of the large equilateral triangle is:

$t = \frac {\Delta_{\rm small}}{\Delta_{\rm large}} = \frac {1^2}{(1+2\sqrt 3)^2} = \dfrac 1{13+4\sqrt 3} \approx 0.050180139 \implies \lfloor 10^6t\rfloor = \boxed{50180}$