2 persons start walking on a road that diverge at an angle of 120 degree. if they walk at rate 3 km/h and 2 km/h respectively. Find the distance between them after 4 hours.

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This Distance can be expressed as a√b km. Find ab
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Where b is a square free integer.

The answer is 76.

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CosC= a^2+b^2-c^2/2ab;

here angle C=120; a=12; b=8;c=?? (as two persons are traveling at the speed of 3 and 2km/h, therefore distance covered in 4 hours will be 3

4=12 and 24=8) Cos 120=-1/2;-1/2=144+64-c^2/2 12*8;

c^2=304;

c=4sqrt(19)

Cheers :)