In the pattern above, each figure after the second is formed by joining three copies of the previous.
The perimeter of each figure is marked in red. The perimeter of the 1st figure is 4, of the 2nd is 8, of the 3rd is 20 and of the 4th is 56.
What is the perimeter of the 6th figure?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
I simply find that the perimeter will satisfy 2 ( 3 n − 1 + 1 ) for n is the number of the figure. So, the perimeter of the 6th figure is 4 8 8
Bisa kepikiran polanya(rumus) kaya gitu gimana ka? atau emang nebak hhe?
Log in to reply
Dari gambarnya sih, kan dia bilangnya 3 kali dari gambar sebelumnya berarti 4 × 3 n − 1 karena awalnya ada 4 sisi, tapi karena yang dicari perimeternya dan ada square yang berhimpit maka sisi yang berhimpit itu bukan perimeter lagi. nah tinggal cari ada berapa sisi yang berhimpit. Kemarin saya dapet polanya 3 n − 1 − 1 (*bisa dicek). Karena sisi yang berhimpit itu merupakan sisi dari dua buah square, maka banyaknya sisi yang tidak lagi jadi perimeter itu ada 2 ( 3 n − 1 − 1 ) .
Jadi, perimeternya 4 × 3 n − 1 − 2 ( 3 n − 1 − 1 ) atau 2 × 3 n − 1 + 2 atau sederhananya lagi 2 ( 3 n − 1 + 1 ) .
Log in to reply
In which language are you talking????
Log in to reply
@Anuj Shikarkhane – Sorry, we are talking in Indonesian (bahasa Indonesia) :(
let the perimeter of nth figure be K. that of n-1 th be L and n-2 th be M. then K=L+3(L-M)
Its easy.just see the difference.4,8,20,56,?,×. 1st difference=4, 2nd difference=12 3rd difference=36... point is there every difference × 3 =Next difference. 4×3=12, 12×3=36 ,36×3=108,108×3=324 Add 108+56=164, 164+324=488 Got the Answer....
for 1st perimeter is 4 and then for 2nd
1*3*4-4=8
Always its increase by 3 so multiply last copies no. to 3. so for 6th copies are 243 and then
243*4-81*4-27*4-9*4-3*4-1*4=488
Problem Loading...
Note Loading...
Set Loading...
It is easy to see that perimeter of a figure is equal to three times perimeter of previous figure minuses 4. Hence perimeter of sixth figure is: ( ( 5 6 × 3 ) − 4 ) × 3 − 4 = 4 8 8