Root 9x

$\sqrt{9 \times x} = 81$ $9 \times x = 81^2$ $x=\frac{81 \times 81}{9}$ $x = \boxed{729}$

$\sqrt{9 \times x} = 81$ Taking $9$ out, $3\sqrt{x} = 81$ $\sqrt{x} = 27$ Squaring both the sides we get, $\boxed{x=729}$

(9x)=81^2. or.x=(81/3)^2. or,x=27^2=729

9 * x=81 * 81

x=6561/9

x=81

\sqrt{9×x}=81 \Rightarrow 3×\sqrt{x}=81 \Rightarrow \sqrt{x}=27 \Rightarrow x=729 (squaring on both sides)

sqrt(9*x)=81

3*sqrt(x)=81

sqrt(x)=27

x=729

Since (9x)^1/2=81, then 9x=81^2=9^4. So x=(9^4)/9=9^3=729.

√9×x=81 Squaring both side 9×x=81×81 X=729

More common sense than math. I knew 3 x 27 = 81. So I just squared 27 to get 729.

whatever operation we do , we do on both the sides , so , we square on both the sides....

(9 x)^.5=81 squaring both side 9 x=81* 81 x=81* 81/9 x=81* 9 x=729