x → 1 lim ( 2 + x 1 + x ) 1 − x 1 − x = n b a
The equation above holds true for positive integers a , b and n , with a and b being primes. Find the value of a + b + n .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
why you do to complicated way if it can done simply?? But nice one
Log in to reply
I was trying a new way to solve such a problem..
Good!, Did it like this. I ddint knew FIITJEE is so advanced...
You know all concepts of XIth and XIIth ?
Log in to reply
Thanks brother...:) Keep uploading questions in future
Log in to reply
You know all concepts of XIth and XIIth ?
I solved It mentally: the only problem is at the exponent but it is in the form (1-x)/(1-x^2) and by semplify and substituting we get to (2/3)^ 1/2 2+2+3=7
Problem Loading...
Note Loading...
Set Loading...
L = x → 1 lim ( 2 + x 1 + x ) 1 − x 1 − x = x → 1 lim ( 2 + x 1 + x ) ( 1 − x ) ( 1 + x ) 1 − x = x → 1 lim ( 2 + x 1 + x ) 1 + x 1 = ( 3 2 ) 2 1 = 3 2
⟹ a + b + n = 2 + 3 + 2 = 7