The figure shows a system with adiabatic walls, a piston and a spring. The space on the left side of the piston is filled with 1 mole of an ideal mono atomic gas and right side is a vacuum with a spring. Initially the system is in equilibrium. Now the gas is heated. Molar heat capacity of the gas in this case is
C
=
2
n
R
. What is the value of
n
is?
(Neglect heat capacities of wall, piston & spring)
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This problem is not correct. Who told you that A x = V ?
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k x = 0 when P = 0 i.e no gas is injected . Hence x is related to volume as A x = V .
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Volume of the gas is A l where l is the length on the left hand side of piston. Agreed? Now how is l = x ? It is not mentioned that the spring is as long as the container.
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@Raghav Vaidyanathan – If we balance forces then force by gas=PA (Initial state)(Left hand side)
Then on the right hand side we have no force as spring is in uncompressed state.
Hence forces are not balanced.
Thus we are left with 1 case.(which is that the pressure due to gas=0)
Do reply.
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@Mahimn Bhatt – Nope, pressure due to gas is not zero. It is given that the spring is initially in compressed state and the system is in equilibrium.
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@Raghav Vaidyanathan – ohk got it
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@Mahimn Bhatt – But basically we need to find out the relation between P and V. That way thinking makes it more easier to solve. Isnt it?
@Raghav Vaidyanathan – Yep thats an error.
In fact this is the third time this problem is posted on brilliant.
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Since Piston is masless , hence Forces are balanced on each side of it .
P g A ∝ K x P g A 2 ∝ K A x P g A 2 ∝ K V P g V − 1 = λ ⇒ x = − 1 C = C v + 1 − x R C = 2 4 R