A geometry problem by Israel Sapnu Jr.

Geometry Level 2

The shortest distance from a point to a circle is 6 and the greatest distance from the same point to a circle is 24. Find the length of the tangent from that point.


The answer is 12.

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2 solutions

Anandhu Raj
Feb 2, 2015

Let P P be the external point and R be the center of the circle. Let MP=6 be the shortest distance. Let NP=24 be the longest distance.

From the data we get that MR=radius of the circle=9

Now consider the tangent PQ , radius RQ=9 and PR=9+6=15 ,

By applying pythagorus theorem in Δ P Q R \Delta PQR , Q = 90 ° \angle Q=90°

P Q = P R 2 Q R 2 \Longrightarrow PQ=\sqrt { { PR }^{ 2 }-{ QR }^{ 2 } }

P Q = 15 2 9 2 \Longrightarrow PQ=\sqrt { { 15 }^{ 2 }-{ 9 }^{ 2 } }

P Q = 12 u n i t s \Longrightarrow PQ=12\quad units

Therefore length of tangent = 12 u n i t s \boxed{12 units}

Just apply P M × P N = P Q 2 PM\times PN = PQ^{2} . You will get answer in a single step.

Purushottam Abhisheikh - 6 years, 4 months ago

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Would you please give me a proof for how the relation came..?

Anandhu Raj - 6 years, 4 months ago

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It is a general relation on circles which is taught to students in class 9 or so.

Purushottam Abhisheikh - 6 years, 4 months ago

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@Purushottam Abhisheikh Oh!! I didn't remember at all.!

Anandhu Raj - 6 years, 4 months ago

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@Anandhu Raj In that case I shall upload its proof.

Purushottam Abhisheikh - 6 years, 4 months ago

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@Purushottam Abhisheikh Then please do upload.

Anandhu Raj - 6 years, 4 months ago

Just to apply the definition power of a circumference

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