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Ok this I understand thanks
i thought....(VI! x VII!):X!=V!(IxII):X=(VxII):X=1
Thanks a lot. What these problems are called?
Thank you, Leonardo. This is a very elegant and simple explanation.
Lovely explanation
its the easiest method ever bro
I cant understand
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You can think of it like this, 10! can be written as 7! X 8 X 9 X 10, as a result you can cancel the 7! from the top and bottom leaving yourself with 6! / 8 X 9 X 10
6! = 720, now cancel the 10 to get 72/8 X 9
8 X 9 is 72 so you are left with 72/72 which equals 1
So is mine
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Zeeshan i know u !! I have talked to u in case of requirement of fiitjee compendium u remember ??
If i solve it in this way - 6! 7!/ 10! = 6! ( 1 * 7 ) /10! = 7/ 10 9 8 7 = 1/ 720
I noticed that
6 ! = 7 2 0 = 8 × 9 × 1 0 = 7 ! 1 0 !
⇒ 1 0 ! 6 ! 7 ! = 1
nice work... thumbs up!
This is a classic case of Catalan Number: knowing the first few terms of the sequence, we get 6 × 7 = 4 2 = C 5 = 5 + 1 1 ⋅ ( 5 1 0 ) = 6 1 ⋅ 5 ! × 5 ! 1 0 = 6 ! × 5 ! 1 0 ! ⇒ 1 = 6 ! × 7 ! 1 0 ! . Reciprocate the expression yields the desired answer of 1 .
+1 for showing the scientific usefulness of 4 2 .
Thanks! I didn't know that!
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You can find out C 6 and it still works out! ⌣ ¨
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Yeah! it works .. amazing! Please suggest a name for the problem.
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@Nihar Mahajan – hehehe "No calculation above fifty"
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@Pi Han Goh – Sure ... troll master .. ⌣ ¨
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@Nihar Mahajan – Actually , I didn't understand the name of this question , can you explain it to me , Genius ?
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@A Former Brilliant Member – I'm no genius. All the other workings needs to show that 6 ! = 8 × 9 × 1 0 = 7 2 0 or 8 × 9 = 7 2 which are well above 5 0 , so setting an arbitrary rule like saying you can't do any arithmetic on a number that gives a resultant number greater than 5 0 makes it more challenging.
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@Pi Han Goh – Ooh! Thanks , I can't believe I never saw that .
Besides , do you plan on creating a message board ? We all can learn from genii like you :)
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@A Former Brilliant Member – I doubt that. We can chat on other platforms. Got an email or something?
@Pi Han Goh – Yeah , foolish on my part .
@A Former Brilliant Member – See Pi Han Goh's solution , it does not need calculations above 50 (actually 42) which is a possible solution , while people will calculate 720 like me..
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@Nihar Mahajan – What ths hell does the ! Mean? I never even seen that.
Can you please explain how you solved this question using combination?!!!
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Do you know the basics of combinations: ( m n ) ?
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Yes I do know about combination
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@Harshit Sharma – After knowing some basic properties of combinations, the next thing you do is read up Catalan's number. Then, voilà! You got the answer.
Noman...how can we post picture there ? This is the easiest n handy way to explain. I tried to post a pic but don't know the medium.
would you please guide me Why 6! = 720?
6!7!/10!
=6!/(10.9.8) [divide top and bottom by 7!]
=6.5.4.3.2.1/10.9.8 [write 6! out]
=3.2.5.2.2.3.2/5.2.3.3.2.2.2 [write as product of primes]
=1
6 x 5 x 4 x 3 x 2 x 1 x 7 x 6 x 5 x 4 x 3 x 2 x 1 / 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 then cancel it all out
6! x 7!/10!
=6! x 7! /10 x 9 x 8 x7!
=6!/10 x 9 x 8
=720/720=1
6! x 7!/10!=6! x 7!/10 x 9 x 8 x7!
We omit 7! It is reduced to 6x5x4x3x2/3x3x2x4x2x5=1
6! X 7! / 10 x 9 x 8 x 7! factorial seven cancelled each other then 720 / 720 = 1
6 ! × 7 ! = 2 2 × 3 2 × ( 2 2 ) 2 × 5 2 × ( 2 × 3 ) 2 × 7 = 2 8 × 3 4 × 5 2 × 7
1 0 ! = 2 × 3 × 2 2 × 5 × ( 2 × 3 ) × 7 × 2 3 × 3 2 × ( 2 × 5 ) = 2 8 × 3 4 × 5 2 × 7
6 ! × 7 ! = 1 0 ! ⇒ 1 0 ! 6 ! × 7 ! = 1
(6! 7!)/10! =(1 2 3 4 5 6 1 2 3 4 5 6 7)/1 2 3 4 5 6 7 8 9 10 =(1 2 3 4 5 6)/(8 9*10) =720/720 =1
It's italicized because you put the asterisks, and something between 2 asterisks is italicized . You need L A T E X .
simple... 1 0 ! 6 ! ∗ 7 ! = 8 ∗ 9 ∗ 1 0 1 ∗ 2 ∗ 3 ∗ 4 ∗ 5 ∗ 6 =1 therefore, ans.= 1
How do you know 6!/(8x9x10)=1? Then, you can move on to “therefore,”.
6! X 7! /10! = 6!/(8 * 9 * 10) = 1 as both are 720 or by canceling like terms in 5 * 2, 3 * 2, 2 * 2 and 3
How do we know that 6! / 8 * 9 * 10 = 1?
You prime-factor it.
6!= 6 x 5 x 4 x 3 x 2 x 1
7!= 7 x 6 x 5 x 4 x 3 x 2 x 1
10!= 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 10 x 9 x 8 x 7!
6! x 7!/ 10! = 6! x 7!/10 x 9 x 8 x 7! = 6!/ 10 x 9 x 8 = 6 x 5 x 4 x 3 x 2 x 1/ 10 x 9 x 8 = 6 x 5 x 3 x (4 x 2 x 1)/10 x 9 x 8 =6 x 5 x 3 x 8/10 x 9 x 8 = 6 x 5 x 3/ 10 x 9 =90/90= 1
I included every step just in case anyone is confused! Hope it helps 😊
6! 7! / 10! = 6 5 4 3 2 1 7!/10 9 8 7! =2 3 5 4 3 2 1/2 5 3 3 4 2 =2 3 5 4 3 2 1/2 3 5 4 3 2 =1
See what I told @Rakibul Hasan Emon on this question
1x2x3x4x5x6x1x2x3x4x5x6x7/1x2x3x4x5x6x7x8x9x10 =2x3x4x5x6/8x9x10=1
7!×6!\10!
6!/10×9×8
720/720
1
1 0 ! 6 ! ∗ 7 ! = 1 0 ∗ 9 ∗ 8 ∗ 7 ! 6 ! ∗ 7 ! = 1 0 ∗ 9 ∗ 8 6 ∗ 5 ∗ 4 ∗ 3 ∗ 2 6 ! : 3 0 , 1 2 0 , 3 6 0 , 7 2 0 1 0 ∗ 9 ∗ 8 : 9 0 , 7 2 0 7 2 0 7 2 0 = 1
simple fac logic 6! 7!/10! 6!/10 9*8 6!=720 so answer 1
6! x 7! = 3628800 10! = 3628800 3628800/3628800=1
Really easy!
What if it really big number like 12! Or 24! You can't do that way
6! 7!/10!=6! 7!/10 9 8*7!=720/720=1
(6!X7!)/10! =(720X5040)/3628800 =3628800/3628800 =1
(6!×7!)/10! (6×5×4×3×2×1×7!)/(10×9×8×7!)=(6×5×4×3×2×1)/(10×9×8)=1
7!6!/10! 7!6!/10 9 8 7! 6!/10 9 8 120 6/720 720/720 1
In easier form, 6 X 5 X 4 X 3 X 2 X 1 X 7 X 6 X 5 X 4 X 3 X 2 X 1
10 X 9 X 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1
= 6 X 5 X 4 X 3 X 2 X 1 _ _ _ _ _ __ 10 X 9 X 8 = 1
Just expand this and cancel all the factors and rada u get the answer
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Since 1 0 ! = 1 0 × 9 × 8 × ( 7 ! ) ,
1 0 ! 6 ! × 7 ! = 1 0 × 9 × 8 × 7 ! 6 ! × 7 ! = 1 0 × 9 × 8 6 × 5 × 4 × 3 × 2 × 1 . Then, we can expand the denominator: 1 0 5 × 2 × 9 3 × 3 × 8 4 × 2 6 × 5 × 4 × 3 × 2 × 1 , and canceling common terms gives: 3 × 2 6 × 1 = 6 6 = 1 .