Only One Head

This is easiest to imagine with a tree diagram, but is possible without. Since there are two coin tosses, we can assume independence of events. Now we make a list of possible outcomes.

$\{ HH, HT, TH, TT\}$

Given that these coins are fair, the probability of a $H$ or a $T$ is $0.5$ . From this, we see that the probability of any one of these outcomes $\{HH, HT, TH, TT\}$ is $\frac{1}{4}$ .

Both $\{TH, HT\}$ are an outcome in which only one head appears, so we add up $\frac{1}{4}+\frac{1}{4}$ to give us the final answer of $\boxed{\frac{2}{4}}$ .

2/4 is partly correct. The correct answer should be 1/2. It's because the rule of Mathematics says that every answer must be in simplest form.

Using quantum physics term there is a 50% chance of getting head because of quantum superposition. Given that of 1 is head and 0 is tail this are the possibility 11 01 10 00 and 01 + 10 = 1/4 + 1/4 = 2/4

there are $2^2$ combinations and there are 2 combinations where there is exactly 1 head so the probability is $\frac{2}{4}$

$P=(nCp)(p^r)(q^{n-r})=(2C1)(\frac{1}{2})^1($ $\frac{1}{2})^1$ $=$ $\frac{1}{2}$

or from the choices $\frac{1}{2}$ is equivalent to $\frac{2}{4}$

When two fair coins are tossed simultaneously ,we can get any one of the following four outcomes: HH, TT, HT,TH. From these four outcomes there are two outcomes where head occurs once.Hence the probability of getting head once is 2/4.

Simple question-Simple answer ....The coin has 2 faces so, the chance of appearance of head is 1/2 and because there are 2 coins 2(1/2) = 2/4....

There are 4 ways to flip coins. All heads, all tails, Tails-Heads, and Heads-Tails. The will be 2 with EXACTLY 1 Heads.

HT TH HH TT Thus there are four posibility so probability will be 1/2

Write a solution. Toss may result in Head Head or Head Tail or Tail Head or Head Head. Exactly one head can take place twice in four possibilities. So probability is 2/4 or 50%

Possibility of getting exactly 1 head- 1/2 x1/2 Total ways of getting it- HT, TH (2 WAYS) Answer - 2x (1/2x1/2)- 2x1/4 = 2/4

two coin means 4 possiblity HH HT TH TT since exactly one head , out of four outcome two outcome was there which consist of exactly one head i.e HT & TH so probability is 1/2

total outcomes 2^2=4.so possibility of exactly one head is either HT or TH.so
prob(exactly one head)=possible outcomes / total outcomes =2/4=1/2