After Christmas 2016!

Let's compute a few powers of $6$ .

$6^1 = \color{#D61F06}{6}$

$6^2 = 3\color{#D61F06}{6}$

$6^3 = 21\color{#D61F06}{6}$

$6^4 = 129\color{#D61F06}{6}$

$6^5 = 777\color{#D61F06}{6}$

Any power of $6$ , or number ending in $6$ , will end in $6$ .

Thus, $1226^{2016}$ ends in $6$ .

6^any number n belongs to natural no last digit is 6 then 1226^2016last digit is 6