A calculus problem by Aman Dubey

Calculus Level pending

if f ( x ) = x 3 + 3 x + 2 f(x) ={ x }^{ 3 }+3x+2 and g ( f ( x ) ) = x g(f(x))=x and h ( g ( g ( x ) ) = x h(g(g(x))=x for all x R x\quad \in \mathbb R then find h ( 1 ) { h }^{ ' }(1) .

Notation : R \mathbb R denotes the set of real numbers .

333 0 666 111

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1 solution

Aman Dubey
Jul 22, 2016

we have h ( g ( g ( x ) ) = x { h }(g(g(x))=x

put x = f ( x ) x = f(x)

\Longrightarrow h ( g ( g ( f ( x ) ) = f ( x ) { h }(g(g(f(x))=f(x)

\Longrightarrow h ( g ( x ) = f ( x ) { h }(g(x)=f(x) and do it again

\Longrightarrow h ( g ( f ( x ) ) = f ( f ( x ) ) { h }(g(f(x))=f(f(x))

So we have

h ( x ) = f ( f ( x ) ) h(x) = f(f(x)) and now you know.

Exactly :)

Aniket Sanghi - 4 years, 10 months ago

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this is 2016 JEE Advanced question.

Aman Dubey - 4 years, 10 months ago

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This was q in a test in my FIITJEE phase test !

Aniket Sanghi - 4 years, 10 months ago

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@Aniket Sanghi Hey Same here... I am in FIITJEE Ghaziabad and u?

Aman Dubey - 4 years, 10 months ago

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@Aman Dubey FIITJEE Raipur , yr phase test score?

Aniket Sanghi - 4 years, 10 months ago

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@Aniket Sanghi 204 in Mains And 172 in Advanced. I think maths Paper 1 (Adv.) was tough I attempted just 4 question in it.

Aman Dubey - 4 years, 10 months ago

@Aniket Sanghi And Yours?

Aman Dubey - 4 years, 10 months ago

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@Aman Dubey 345 in Mains , 293 in advance ( 129 + 164 )

Aniket Sanghi - 4 years, 10 months ago

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