Quick Sine Calculation

Geometry Level 1

sin ( 3 0 ) = ? \Large \sin \left(30^\circ\right) = \ ?

3 2 \frac { \sqrt { 3 } }{ 2 } 1 2 \frac { 1 }{ 2 } 1 1 0 0

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2 solutions

Discussions for this problem are now closed

U Z
Dec 3, 2014

awesome Solution ! Really very tough problem :) :)

Deepanshu Gupta - 6 years, 6 months ago

Yes very tough problem, but in a way its good too , suppose whoever discovered the sin , cosine , and all the function dependent on them, at that time it would be good thing to have prove it , because i read in a Isaac asimov book that people used to do geometry i.e measuring angles and creating figures by sticks.

Nowadays too people are not leaving this habit, many rich people are fond of things made of sticks , moreover many exhibition are also held on this work. This also proves that we inherit some characters( or habits) from our ancestors - i.e it proves the theory of The great - Gregor Johannan Mendel

See some figures - people are enjoying this work today

Its title should be - show your method i think so

U Z - 6 years, 6 months ago

I cant understand sin , please help.

Anish Harsha - 6 years, 6 months ago

@Anish Harsha Check out the Trigonometry Practice Section , which will guide you through understanding these trigonometric functions!

Calvin Lin Staff - 6 years, 6 months ago

@Calvin Lin is the first figure icosahedron??

Gaurav Jain - 6 years, 5 months ago

the first one is an incredible figure.The second one however represents the relationship between plane and solid angle(measured in steredian). Can any one explain the first figure please?...

AnWesa Royce - 6 years, 6 months ago

Thanks a lot For Sharing This Info ! I also Loved The Handicrafts ! They are Pleasant to our eyes !

Deepanshu Gupta - 6 years, 6 months ago

Why did you reshared this, Megh?

Ninad Akolekar - 6 years, 6 months ago

@Ninad Akolekar Want to see others approach

U Z - 6 years, 6 months ago
Julian Uy
Dec 15, 2014

In a 30-60-90 triangle, the side opposite the 30 degree angle is always half of the hypotenuse. Since sine=opposite/hypotenuse, sin30 = 0.5 \boxed { 0.5 } .

Exactly what I used. Always remember your special right triangles.

Michael Bartholic - 6 years, 3 months ago

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