An algebra problem by Syed Baqir

Algebra Level 2

Peter makes a large amount of pink paint by mixing red and white paint in the ratio 2:3. Red paint costs £40 per 5 litres. White paint costs £5 per 10 litres. Peter sells his pink paint in 10-litre tins for £60 per tin. Calculate how much profit he makes for each tin he sells.

30 15 27 25 6

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Denton Young
Sep 8, 2015

Each 10-litre tin of pink paint contains 4 litres of red paint (cost: 40 * 4/5 = 32) and 6 litres of white paint: (cost: 5 * 6/10 = 3), so the total cost is 32 + 3 = 35. Profit on each tin is therefore 60 - 35 = 25.

Moderator note:

Simple standard approach using ratios.

Can you add some more lines: I mean ::

40 * 4 5 \frac{4}{5} = 32

where: 40 = Price or Red Paint,

BUT 4 5 \frac{4}{5} = ??

Syed Baqir - 5 years, 9 months ago

Log in to reply

If the price is 40 for 5 gallons of red paint, then for 4 gallons it is 4/5 that amount.

Denton Young - 5 years, 9 months ago

Log in to reply

Yes, The main thing is to add some lines so it can help every one because few people dont know how to analyse 2:3

Syed Baqir - 5 years, 9 months ago

Log in to reply

@Syed Baqir Here's another way to look at it. If the ratio of red to white is 2 to 3, then let's have Peter make up 50 litres of pink paint. He will use 20 litres of red (at 40 for 5 litres, that's 160) and 30 litres of white (at 5 for 10 litres, cost is 15) for a total cost of 175. He will sell it at 60 for 10 litres, so for 50 litres that's 300. Total profit = 300 - 175 = 125 for 50 litres of pink. So for 10 litres of pink profit is 125/5 = 25.

Denton Young - 5 years, 9 months ago

Log in to reply

@Denton Young Nice, Great Explanation .

Syed Baqir - 5 years, 9 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...