A rational game 4

Algebra Level 3

A polynomial with integer coefficients P ( x ) = a n x n + a n 1 x n 1 + + a 0 P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{0} , with a n a_{n} and a 0 a_{0} being positive integers , has one of the roots 2 3 \dfrac{2}{3} . Find the fourth smallest possible value of a 0 + a n a_{0}+a_{n} .


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The answer is 9.

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1 solution

Prince Loomba
Jun 17, 2016

a 0 = 2 x a_{0}=2x and a n = 3 y a_{n}=3y because according to rational roots theorem, 2 2 is factor of a 0 a_{0} and 3 3 is factor of a n a_{n} . Thus we need fourth smallest value of 2 x + 3 y 2x+3y , which is obtained when x and y are 3 and 1 respectively. Hence answer is 6 + 3 = 9 6+3=9

Do you have to find all initial maximum values? Is there a better way to solve for maximum values(in order) of this kinda equation?

Akshay Krishna - 2 years, 6 months ago

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https://brilliant.org/problems/a-rational-game-ends/ see this problem once!

Prince Loomba - 2 years, 4 months ago

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Thanks :) Do you mean induction is the most efficient way?

Akshay Krishna - 2 years, 4 months ago

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@Akshay Krishna I didn't ever say it's the most efficient way... Try to find a better one!! Though I think induction is a good way at least.

Prince Loomba - 2 years, 2 months ago

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