A second pendulum

Classical Mechanics Level 2

A second pendulum length is increased by $300\%$ or $3$ times

what is its period of oscillation(seconds)?

Note: A seconds pendulum is a pendulum whose period is precisely two seconds.

3.6 1.8 2 4

1 solution

Nazmus Sakib
Nov 21, 2017

$T_{1}=2\pi \sqrt{\dfrac{L_{1}}{g}}$ ......(1)

$T_{2}=2\pi \sqrt{\dfrac{L_{2}}{g}}$ ........(2)

Here,

$L_{1}=L$

$T_{1}=2s$

$L_{2}=300\% L+L=3L+L=4L$

Now,from equation (1) and (2) we get,

$\dfrac{T_{2}}{T_{1}}=\sqrt{\dfrac{L_{2}}{L_{1}}}=\sqrt{\dfrac{4L}{L}}=\sqrt{4}=2$

So,

$T_{2}=2T_{1}$

$T_{2}=2\times 2 s$

$T_{2}=4s$

Where have you get T1= 2s??!!

shithil Islam - 3 years, 6 months ago

A seconds pendulum is a pendulum whose period is precisely two seconds. see more

Nazmus sakib - 3 years, 6 months ago

Ooooo....look....I'm in class 9...I don't know about pendulum very much.....so I think you have to assume it..... It is better for others....

shithil Islam - 3 years, 6 months ago

@Shithil Islam – I've edited the question.Now does it looks better?

Nazmus sakib - 3 years, 6 months ago

@Nazmus Sakib – yup.......;)

shithil Islam - 3 years, 5 months ago