A stable ball

The center of mass of a solid hemisphere of radius $R$ is $\frac 38 R$ from the center of the sphere normal to the flat surface of the hemisphere. Since the density of iron is $7.27 \text{ g/cm}^3$ and that of wood is $0.39 \thicksim 0.60 \text{ g/cm}^3$ , the center of mass of the ball is approximately $\frac 38 R$ from its center in the iron hemisphere (shown as red dot in the figure). The most stable position of the ball is when it has the lowest potential energy $mgh$ , where $m$ is the mass of the ball, $g$ the acceleration due to gravity and $h$ the distance from the flat surface. As $m$ and $g$ are constant, the lowest potential energy occurs when $h$ is smallest. Of the four positions, $\boxed B$ has the smallest $h$ and hence the most stable position.

violets are blue, roses are red, iron is heavier so anyone telling the answer isn't B would be mad.

Iron is much more dense than wood. Since the volume of each material in the ball is the same, this means that the iron half weighs more. As there is more weight in the iron half, the iron half will be at the bottom when it comes to rest, making it answer $\boxed{\text{B}}$ .

If you would like a confirmation that the iron half will most likely be on the bottom, imagine the ball as shown in option A, with a bit of kinetic energy still. The centre of mass is on the right, meaning that it will roll slightly to the right, making the iron on the bottom. Now that the centre of mass is central, the ball is unlikely to roll as much. Also, note that the centres of mass of options A and C are off centre, whereas although D is central, the centre of mass is slightly higher up, meaning it is more likely to be B.

Iron is heavier than wood

If you think intuitively,you will find that as the ball rolles,and when the iron half is above there will be a greater torque devepeloped even on slight rolling than when the wooden half is on top.hence the position with the iron half at bottom is most stable

The iron is more dense than the wood, so the center of gravity of the ball would be closer to the iron side than the wood side. Objects tend to move towards positions where the center of gravity is closest to the ground, and in position B the iron part is closest to the ground.

The pull of gravity is stronger in the iron because it is more dense

B

Stability is finding the Center of gravity (point of even distribution of the mass) of the entire object and the closer the center of gravity to the ground the stable the object will be and in this case (B) is the answer ( the mass is well distributed its center of gravity is in the lower center in the (half iron) near the ground. For A the iron right side(half iron) has more weight so the center of gravity is on the right most which makes it not stable, For C left side has more weight(half iron) so the center of gravity of the object is in the left most not stable, For D it is stable it will not move since the center of gravity is in place where the mass is well distributed but a slight movement will make D move easily due to the center of gravity is at the upper most where most of the mass of half iron is located so D is next to B when it comes to stability.

Because iron is heavier than wood which is obviously true since metals are damn heavy. So it will probably be at the bottom after the ball rolls. Same if you threw it into water. Except it will mid- float.

The correct answer is (B).There are many reasons why the iron part will be in contact with the ground at rest . The best solution to this problem is the concept of density, mass and weight. The iron and wood part have equal volumes but as iron is denser it means that iron has more weight than the wood in the following example. As the of iron is more than that of wood the centre of mass would be towards the iron half and objects tend to face the ground with the centre of mass pointing towards the ground. Hence , option (B) is the correct answer

To keep it simple: The Wood is light, The Iron is heavy, Gravity pulls on everything.

roses are red, violets are blue, iron is heavier so the answer is b

This was too easy, I almost thought it was a trick question.

We know that iron is heavier than wood,so the ball central of mass is located on the ball iron side. $\color{#3D99F6}{\boxed{\large{B}}}$ is the answer because the ball central of mass is lowest & the most stable position.

Iron is heavier than wood so it must land on the heavy side which is iron

$Iron\ is\ heavier\ then\ wood\ so\ the\ answer\ is\ B$

iron is heavier than wood

The center of mass is at the middle of the iron because iron is more dense. Therefore, the correct answer is b

Gravity pulls heavier objects with more force, since the iron is heavier it will be the lowest.

Iron is heavier than wood, so therefore it is B.

Iron outweighs and creates inertia,the wood acts as a light counter weight and will always be on the opposite end of the iron.

I think this problem is essentially explains how roly-poly toys (wobbler man) work. Link here

A and C are equally as likely so neither of them could be it. But D has its center of mass on the upper portion of the ball which results in it flipping over and becoming B therefore B is the most likely.

Since iron is more dense than wood, surely it would be situated at the bottom. This hypothesis is simply based on the topic of density (mainly taught in physics and perhaps in maths) which stresses that lighter (less dense) objects are always on top of the more dense object. Obviously don't simply base your scientific knowledge on all maths questions since most questions require you to actively calculate figures and apply them to the question. But in this instance, it was particularly straightforward to those who knew density prior to answering the question.

It's obvious that the answer isn't A or C since the iron half is denser than the wooden half.

D is also out because iron is denser so it can't be on top of the wooden half.

Thus, the answer is B.

Iron weighs greater than wood

I'd like to give a short answer: Iron's density is more than that of wood's. Simple.

Shouldn't you quantify that the ball is solid, or otherwise state that the two materials have the same thickness? You could conceivably have a solid dense wood and very thin iron half sphere that still represents a ball that is half and half, and subsequently reacts differently than what you originally intended....