A trip around the world!

Logic Level 4

There is an air base on the equator. The maximum amount of fuel that a plane can contain would be only sufficient for it to fly halfway around the world.

For at least one plane to finish a trip around the world, how many planes do you need at least?


Details and assumptions:

  • Same plane doesn't depart twice or more.

  • Ignore all scientific and aerodynamic facts such as revolution of the earth or evaporation of the fuel. The airplanes can use their fuel until it's empty. Starting the airplane doesn't take any time.

  • Every plane moves at the same speed, and on the same airway.

  • Assume the planes and air base are dimensionless, and thus, can turn directions instantly.

  • The plane can only be fueled via aerial refueling, and the amount of time the process takes is negligible.

  • Every plane starts at the air base and must return to the air base.

3 7 8 The trip is impossible. 5 6 4 16

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1 solution

Boi (보이)
Jul 21, 2017

The earth is round.

Let's call a "trip" a clockwise revolution around earth.


(1)

First, three planes start from the air base. At 1 / 8 1/8 of the trip, all planes have 3 4 \dfrac{3}{4} of their fuel.

One plane gives the other two 1 4 \dfrac{1}{4} respectively, and returns to the air base with its fuel 1 4 \dfrac{1}{4} left.


(2)

Then two planes continue going. At 1 / 4 1/4 of the trip, both of them have 3 4 \dfrac{3}{4} of their fuel.

One plane gives the another 1 4 \dfrac{1}{4} , and returns to the air base with its fuel 2 4 \dfrac{2}{4} left.

Then one plane is left, with its fuel full.


(3)

At 1 / 2 1/2 of the trip, the plane's got 2 4 \dfrac{2}{4} of its fuel left.

Then the trick happens. One plane starts off at the air base, going to the opposite direction where the first three airplanes went.


(4)

The two planes would meet at 3 / 4 3/4 of the trip, and one plane would have its fuel empty, and the other, 2 4 \dfrac{2}{4} .

The two planes then share the fuel fairly so that both of them would have 1 4 \dfrac{1}{4} each.

At the moment that happens, another plane starts off at the air base, going to the direction of the fourth airplane.


(5)

The three planes would meet at 7 / 8 7/8 of the trip, and two of them would have its fuel empty, and the other, 3 4 \dfrac{3}{4} .

The three planes then share the fuel fairly so that each of them would have 1 4 \dfrac{1}{4} .

The three planes return to the air base, and at the moment they arrive, all of their fuel tanks gets empty.


Therefore we need 5 5 planes to do this, and it is impossible to do it with less planes.

That is not true! What if we used the same 2 planes that accompanied the main plane in the beginning, accompanied the plane in the end? Then the answer would be 3!

Siva Budaraju - 3 years, 10 months ago

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Elaborate your procedure more precisely. I'm not clear about what you meant.

Note that when a plane goes 1/4 way through, in order to bring the supporting plane back, the plane cannot afford to give any of its fuel to the other airplane and thus must come back.

Also, to clarify, there does exist a condition in "DETAILS AND ASSUMPTIONS" that all planes must come back to the air base. And that means, none should be abandoned.

Boi (보이) - 3 years, 10 months ago

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I know. I meant, that once the first 2 planes come back, you can use them again when the trip is almost done. So you will end up using 1 plane once and 2 planes twice, for a total of 5 flights, but only 3 planes total.

If you are still confused, watch this video: https://www.youtube.com/watch?v=dzrwnwOx0fw for a proof that it can be done with 3 planes.

Siva Budaraju - 3 years, 10 months ago

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@Siva Budaraju Okay I revised the question. Does the question make sense now?

Boi (보이) - 3 years, 10 months ago

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@Boi (보이) Yes, but I think you should make "No plane can depart more than once" a separate bullet point, so that it will be more clear.

Siva Budaraju - 3 years, 10 months ago

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@Siva Budaraju Okay, thanks! :D

Boi (보이) - 3 years, 10 months ago

Did you imply that aerial refueling is possible between two planes?

Atomsky Jahid - 3 years, 7 months ago

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Please read the condition.

"The plane can only be fueled via aerial refueling, and the amount of time the process takes is negligible."

Boi (보이) - 3 years, 7 months ago

Furthermore, To decrease take-off load, the SR-71 Blackbird's fuel cells were only partially filled. The SR-71 had to be immediately refueled once it was airborne from a KC-135Q Stratotanker.

Flynn Collins - 3 years, 3 months ago

If 2 planes took of from the base, if at 1/4 of the way around the world, the First plane filled the Second plane all the way, it would still have enough fuel to complete the trip back to the air base. The Second Plane, now with a full fuel tank, travels to the 3/4 mark of the trip. There it will meet the Third plane which repeats the fueling process mentioned above. Now both planes have enough fuel to make it back to the Plane base. So the question stands, can't you complete the trip with 3 planes?

Flynn Collins - 3 years, 3 months ago

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