A tunnel is dug in the Earth's crust joining any 2 points on surface (not diametric end points). Now a long spring of length l(l < 1/4th length of chord ) is attached to the mid point of chord .To the other point of the spring , mass of m is attached.
Find the Time-period of SHM , if a constant force of 100 N is applied in the direction so as to extend spring.
Your answer can be represented as 2 π a sec.
Enter a as your answer.
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The question is not at all as difficult as it looks .
Note that The constant force would not be responsible for SHM Of body it would be merely shifting the equilibrium position. (like we ignore gravity in a simple spring block vertical system).
Write the restoring force along the tunnel as a function of displacment of spring. Now restoring force would be the combination of spring force and gravitational force.
Spring force = Kx . and gravitational force along the tunnel = GMmx/R^3.
You can obtain the second expression by resolving the gravitational force along length of tunnel. (Note- Gravitational field intensity inside a solid sphere is given By GMx/R^3 where x is distance from the centre)
Just compare this with standard differential equation of SHM And find time period)