Find $a, b, c$ which are real numbers that satisfy

${ a }^{ 2 }+{ b }^{ 2 }+{ c }^{ 2 }=0.$

0,1,0
-1,0,1
0,0,0
1,0,-1

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Did he have to give it as an MCQ question? Way too easy.

Joshua Ong
- 6 years, 11 months ago

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Exactly! He could have asked for like $a+b+c$ or something. :P

Finn Hulse
- 6 years, 11 months ago

whyy??? invisibLe by 1 right??? so it is (1,1,1)

Christian Dialino
- 6 years, 8 months ago

Square of a real number is always Non negative i.e. $(-1)^{2} = 1$ $(-2)^{2} = 4$ $(-0.5)^{2} = 0.25$ $(0)^{2} = 0$

so the sum of 3 non negative is equal to zero only when each number is equal to zero

$a^{2} = b^{2} = c^{2} = 0$ implies $(a,b,c) = (0,0,0)$

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Thanks to clear my doubt

abudahir 617
- 5 years, 7 months ago

Zero squared= 1 so this whole question is wrong

Josh Murley
- 6 years, 1 month ago

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0^2=0×0=0 not 1 You might be confusing this for 0! Which is equal to 1 or 0^0 which is not defined.

Sonali Sinha
- 5 years, 11 months ago

You are right! This question is impossible to solve. Zero squared is equal 1. No answer given satisfy this condition.

Cezário Abrantes
- 6 years ago

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no, 0^x=0, x^0=1

Nota Xue
- 5 years, 9 months ago

0 squared means 0x0 And I think that you know 0x0 so how can you say that 0 squared is 1

Sonal Singh
- 5 years, 9 months ago

I agree zero to any power is 1. The whole question is invalid.

Jessica Beck
- 5 years, 9 months ago

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@Jessica Beck – No absolutely not, the questions is valid in 0^2=0

Jan Grünwaldt
- 5 years, 5 months ago

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Real numbers can be positive, negative, or $0$ .

Daniel Liu
- 6 years, 11 months ago

If the author was looking for positive real numbers, he would be asking for 'positive reals'.

Victor Loh
- 6 years, 11 months ago

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a=0 b=0 c=0 0^2=0 zero squre values of also calculate zero ( a b c)=(0 0 0)

the answer is 0 0 0

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0squ.+0squ.+osqu=0 n ans 0,0,0

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It is very easy ; since , a.a + b.b + c.c =0 { says equation 1 } by equation 1 we have , a.a = b.b = c.c = 0

so ; ( a,b,c ) = ( 0,0,0 ) .

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in all option only this option is having real number so ans is 0,0,0

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-1 square will give you +1 so only one possibility i.e. 0 0 0

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The square of a real number is non-negative. Hence $a^{2}=b^{2}=c^{2}=0\implies (a,b,c)=\boxed{(0,0,0)}$ and we are done.