Find a , b , c which are real numbers that satisfy
a 2 + b 2 + c 2 = 0 .
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Did he have to give it as an MCQ question? Way too easy.
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Exactly! He could have asked for like a + b + c or something. :P
whyy??? invisibLe by 1 right??? so it is (1,1,1)
Square of a real number is always Non negative i.e. ( − 1 ) 2 = 1 ( − 2 ) 2 = 4 ( − 0 . 5 ) 2 = 0 . 2 5 ( 0 ) 2 = 0
so the sum of 3 non negative is equal to zero only when each number is equal to zero
a 2 = b 2 = c 2 = 0 implies ( a , b , c ) = ( 0 , 0 , 0 )
Thanks to clear my doubt
Zero squared= 1 so this whole question is wrong
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0^2=0×0=0 not 1 You might be confusing this for 0! Which is equal to 1 or 0^0 which is not defined.
You are right! This question is impossible to solve. Zero squared is equal 1. No answer given satisfy this condition.
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no, 0^x=0, x^0=1
0 squared means 0x0 And I think that you know 0x0 so how can you say that 0 squared is 1
I agree zero to any power is 1. The whole question is invalid.
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@Jessica Beck – No absolutely not, the questions is valid in 0^2=0
Something is wrong, they said a,b and c are real numbers [only positive], so how come they all can be zero ?
Real numbers can be positive, negative, or 0 .
If the author was looking for positive real numbers, he would be asking for 'positive reals'.
Square of a real number is always positive. Thus, if 3 positive integers add up to zero there is only one possibility that all the numbers are zeroes.
It's not defined because a,b,c are different variables, they have different values. They can't be 0,0,0
a=0 b=0 c=0 0^2=0 zero squre values of also calculate zero ( a b c)=(0 0 0)
the answer is 0 0 0
It can be also that at least one of the a or b or c is a complex number. This will give a negative value that will get the 0.
if we square any positive or negative number, we will get a positive answer.For example, (1)^2=1 and (-1)^2=1.So, we can never get a negative answer by squaring something. The only way to satisfy the equation is when all a,b,c are equal to zero.,
since 0 square is equivalent to 0, hence all variables should be zero and not 1 whose square is still 1
0squ.+0squ.+osqu=0 n ans 0,0,0
( 0 , 0 , 0 ) i s r i g h t a n s w e r B e c a u s e 0 2 + 0 2 + 0 2 = 0 o t h e r s a r e i n c o r r e c t
It is very easy ; since , a.a + b.b + c.c =0 { says equation 1 } by equation 1 we have , a.a = b.b = c.c = 0
so ; ( a,b,c ) = ( 0,0,0 ) .
since sqare of real numbers ae always non-negative,if sum of three non-negative numbers are 0 then they must be 0.
in all option only this option is having real number so ans is 0,0,0
-1 square will give you +1 so only one possibility i.e. 0 0 0
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The square of a real number is non-negative. Hence a 2 = b 2 = c 2 = 0 ⟹ ( a , b , c ) = ( 0 , 0 , 0 ) and we are done.