A two-digit number is multiplied by twice the sum of its digits. If the new number formed is 1558 greater than the original number. What was the original number?
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best of luck for kvpy!
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Thanx....you didnt appear this year?
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no, but I solved the question paper on 2nd November at home. mathematics was really good.
how was your exam??
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@Shuvam Keshari – Good....could have been better...i should have attempted physics in section 2 instead of maths
how was your Olympiad exams??
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Astronomy was good,in chemistry i got many wrong as i made many guess,and physics was ok...how was yours?
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same here. not much chance in chem!
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@Shuvam Keshari – I think i only have got chance in astro...what do u think will be the cutoff for each?
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@Arpan Konar – i think AT MAX, phy-115, chem-150, astro-150
@Arpan Konar – so, how was your Olympiad exams??
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@Shuvam Keshari – 95 in nsep,119 in nsec and 180 in nsea....and urs?
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@Arpan Konar – 100 in nsep, 161 in nsea and 91 nsec.
physics was much less than expected, and i think i need to start studying chem real hard:(
@Arpan Konar – you know what, i think, it is useless talking on the 'comments' section of this problem. in future join me in google hangouts!!
@Arpan Konar – btw, happy new year and see you on 30th january!
let the number be represented as 10x+y
by framing the conditions in the form of an equation, we get a hyperbola and we may look for the lattice points.
here x can take values-- 1,2,3,4,5,6,7,8,9. we find that only for x=8, we get a reasonable value of y=2
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Let the number be N=10x+y. Hence,N × 2 ( x + y ) = N + 1 5 5 8 Or,N= 2 x + 2 y − 1 1 5 5 8 The factors of 1558 are 1,2,19,38,41,82,779,1558. Since 0 ≤ x ≤ 9 & 0 ≤ y ≤ 9 therefore − 1 ≤ 2 x + 2 y − 1 ≤ 3 5 . Therefore 2x+2y-1 can only be 1,2 or 19 for the left hand side of the equation to be an integer.But when it takes values 1 &2 then N=1558 &779 respectively(which are rejected as N is a two digit number).Hence only 2x+2y-1=19 is possible,then N= 1 9 1 5 5 8 =82(Ans)