Electromagnetic Induction #1

A conducting disc of mass m m and volume v v is suspended with the help a light spring of force constant k k from a fixed support. Thickness of the disc is much smaller than its radius. A uniform magnetic field of induction B B parallel to the plane of the disc is established and the disc is pulled down slightly and released. Find period of the small amplitude oscillations of the disc.

Answer comes in the form of T = α m + β ϵ 0 V B γ k T=\alpha \sqrt{\frac{m+\beta \epsilon_{0}VB^{\gamma}}{k}}

Type your answer as α + β + γ = ? \alpha+\beta+\gamma=?

The problem is taken from my Physics Book [Focus on the problem :) ]

Thanks in advance if you are going to post solution


The answer is 9.283.

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