Just A Fraction

$\dfrac {2013 \times 2014 - 2013 \times 1392}{2014 - 1392} = x$

$\dfrac {2013 \times (2014 - 1392)}{2014 - 1392} = x$

$2013 = x$

It's very simple.

According to the question:

$= \frac{2013\times2014-2013\times1392}{2014-1392}$

Taking $2013$ as common.

$= \frac{2013(2014-1392)}{2014-1392}$

Cancelling $(2014-1392)$ , we get:

$= 2013$

Thus, the answer is: $\frac{2013\times2014-2013\times1392}{2014-1392}=\boxed{2013}$

2013 * 2014 = 4054182

and

2013 * 1392 = 2802096

and

2014 - 1392 = 622

4054182 - 2802096 = 1252086 / 622 = 2013.

Your brain doesn't rearrange numbers really well, but it does variables really well. :-) So let's make them variables.

$\frac{a(a+1)-ab}{a+1-b}$

notice $a$ is in common, use distributive property.

$\frac{a(a+1-b)}{a+1-b}$

they cancel, and you're left with $a$

$a = 2013$

I figured it out this way, I don't know if it's right though, but it came up with the right answer. I took out the first 3 digits of each number and made the equation

( 3 x 4 - 3 x 2 ) / ( 4 - 2 ) = 3 Then I added the first 3 digits back to the number ending in 3 and got 2013.

Let:
A = 2013
B = 2014
C = 1392
$\frac{{A}\times{B}-{A}\times{C}}{{B}-{1392}}=x$
Using the Distributive Property of Multiplication
$\frac{{A}\times{(B}-{C)}}{{(B}-{C)}}=x$
We can cancel out (A-B)
x=A
A=2013
x=2013

Factoring the expression: $\begin{aligned} \frac{\textcolor{#20A900}{2013} \times \textcolor{#3D99F6}{2014} - \textcolor{#20A900}{2013} \times \textcolor{#D61F06}{1392}}{\textcolor{#3D99F6}{2014} - \textcolor{#D61F06}{1392}} &= \frac{\textcolor{#20A900}{2013}(\textcolor{#3D99F6}{2014} - \textcolor{#D61F06}{1392})}{\textcolor{#3D99F6}{2014} - \textcolor{#D61F06}{1392}} \\ &= \boxed{\textcolor{#20A900}{2013}} \end{aligned}$ Therefore, the answer is 2013 .

2013 x 2014 -2013 x 1392/2014 - 1392

=2013(2014-1392) / (2014-1392)

=2013

a = 2013 b = 2014 c = 1392

(a b-a c)/b-c = (a(b-c))/b-c cancel b-c = a

Ans = a

Using the distributive property, $\frac{2013 \times 2014-2013 \times 1392}{2014-1392)}$ will become $\frac{2013 \times (2014-1392)}{2014-1392}$ . Let's say the unknown is y. After a bit of calculation, you can find out that y=2013.

$\frac{2013 \times 2014-2013 \times 1392}{2014-1392}=\frac{2013(2014-1392)}{2014-1392}=\boxed{\large{2013}}$

A simple case of factorising:

= 2013 ( 2014 - 1392 ) / (2014 - 1392 ) = 2013 / 1 = 2013

note: a bit naughty to not include brackets in the question. I wouldn't be happy if such a question was faced by a student in a GCSE exam without clear instruction of whether to treat it with BIDMAS or number machine value by value process.

Just factor and solve

$\frac{2013*2014-2013*1392}{2014-1392}$ = $\frac{2013(2014-1392)}{2014-1392}$ (by taking 2013 common in both equations) = $\frac{2013*622}{622}$ (by cancelling numerator and denominator) = 2013

This looks confusing at first, but it is actually easier than you think.

$2012 \times 2014 - 2013 \times 1392 \over 2014 - 1392$

So, $2012(2014-1392)\over 2014-1392$

Cancel common terms and you'll end up with 2013.

Keep 2013 as "x".

So,

X * (x+1) - (x * (x-621) / (x+1) - (x-621)

(X^2 + x - X^2 + 621x) / (x + 1 - x + 621)

622x / 622

Then we are left with just "x", so the answer is X=2013.

2013(2014-1392)/2014-1392=2013

See the denominator.... And take 2013 common.... Divide... U will get the solution

To simplify:

$\frac{2013\times2014-2013\times1392}{2014-1392}$

Taking common:

$=\frac{2013(2014-1392)}{2014-1392}$

Let $(2014-1392)$ be $x$ .

Replacing $(2014-1392)$ with $x$ :

$\frac{2013x}{x}$

Eliminating the $x$ s:

Final answer: $\boxed{2013}$

Quite simple. Use variable substitution, as so!:

$(\frac { 2013\times 2014-2013\times 1392 }{ 2014-1392 } )$

Now, just replace each number with a variable, as follows: $a=2014, b = 2013, c = 1392$

Now, solve through simple substitution & simplifying the fraction: $\frac { ab-ac }{ b-c }$

When in doubt, factor it out ;) $\frac { a(b-c) }{ (b-c)}$

One more step of canceling out the (b-c)s, and we're done!: $\boxed{a = 2014}$

Just Cross out the same numbers from the top and bottom for example 2014 and 1392 which leaves you with 2013

I did like this: Since some had same colour.. It can now become a b-a c/b-c Now divide it using division in algebraic method. And u will directly get (a) i.e 2013

(a b-a c)/(b-c) = (a*(b-c))/(b-c) = a

2013(2014-1493)/2014-1493= 2013

2013(2014-1392)/2014-1392 equal to 2013*22/22 equal to 2012

Very simple

. 2,013 x 2,014= 4,054,182

.2,013 x 1,392 = 2,802,096

.4,054,182 - 2,802,096 = 1,252,086

.2,014 - 1,392 = 622

.1,252,086 / 622 = 2013 answer

Let a=2013 b=2014 c=1392 The equation becomes (ab-ac)/(b-c)=a (b-c)/(b-c)=a Substituting a, the answer is a=2013.

take 2013 common from numerator and cancel the remaning small bracket data by denumenator.....2013 will left...which is the answer of given question

2013( 2014-1392)÷(2014-1392)=2013

Let 2013 be x. Let 2014 be y. Let 1392 be z.

(xy) - (xz)

  y - z

= x (y - z) (Bring x factor out)

   y - z

= x

Ans: x= 2013,, 😊

2013(2014-1392)/2014-1392= Note:get the common factor THen you can now cancelled out So, The answer is 2013

Purely easy solution take out 2013 as common part in numerator then we get 2013(2014-1392) and now cancel numerator part n denominator part 2013(2014-1392)/(2014-1392)=2013 Simple :)

Factor out the 2013, and then you have the answer. Simple as that.

(2013*(2014-1392))/(2014-1392)=2013

2013(2014-1392)/2014-1392

2013

2013(2014-1392)/2014-1392=2013

2013 is the right answer because all the same digit will cut and only 2013 will remain .

cancel out the same figures!